Sudoku solution – New York Times sudoku 21 May 2023 Hard level

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Solved in 19 min.Tough entertaining Hard puzzle. Good puzzle Thanks.

Ramakrishnagm

At 8m40, having reviewed the 79 pair from box 3 and the matching position of the pair of 7s in box 9, flirted with the 9s wondering whether they would be in r7c7 or r8c7. If in row 7, you have a UR conflict. The 9 in row 8 is the only solution. The 9 placed there has dramatic impact all over the grid and in fact, makes the rest of the game rather easy.

georgesthibaudeau

Aha, I did this puzzle using pencil and paper earlier today, went as far as I could without notation, but got stuck. Seeing I was having a go at it between scenes of running through an opera I am about to do, I had to resort to some pencil marking in order not to have to work out what pairs went where every time I picked it up. I got there in the end with limited (certainly not full) notation.

grahamfisher

Mmm, quite a challenge today, even with a UR (31 = row 3 column 1):
31, 14, 25, 12, 23,
11, 33, 97, 94, 87 (UR, boxes 3 and 9),
71, 39, 37, 79, 99,
83, 84, 77, 28, 27,
58 (pair in box),
97, 98, 52 (well-hidden single),
91, 93, 61, 41, 92,
53, 66, 49, 17, 19,
67, 56, 35, 36, 85,
69, 45, 65, 42, 62,
48, 68, 43, 63, 44,
64, 76, 86, 72, 82,
74, 59.

And even more so without the UR:
27 instead of 87 (triple in column),
28, 58 (pair in box),
98, 52 (hidden single),
66, 49, 17, 19, 67,
56, 91, 35, 36, 85,
64, 44, 92 (pairs in column),
63, 41, 99, 83, 76,
86, 72, 82, 74, 94,
71, 93, 43, 68, 48,
62, 42, 65, 45, 53,
61, 59, 69, 97, 87,
39, 37, 79, 77.

Edited to make correction.

AnonimityAssured

13.09. A bit harder than others recently

gr

... par (7, 9) en 3a fila, par (1, 8) en 2a fila y par (3, 6) en 1a fila dentro del bloque 3; pares (3, 5) y (6, 8) en 3a fila ent (3, 1)=8 (3, 3)=6 (1, 1)=5 (2, 3)=3; par (3, 4) en 2a col dentro del bloque 7; tercia (1, 3, 8) y par (7, 9) en 8a col dentro del bloque 6; cuaterna (1, 3, 4, 6) en 9a col ent (9, 9)=2 (8, 3)=2 (7, 1)=9 (8, 7)=9 (3, 7)=7 (3, 9)=9 (7, 9)=7; tercia (1, 5, 6) en 9a fila dentro del bloque 7, ent (9, 8)=3 (5, 8)=8 (2, 8)=1 (2, 7)=8 (9, 7)=4 (7, 7)=1 (8, 4)=1 (5, 2)=6...

hectormejia

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