How to accept USER INPUT using Java! ⌨️

#java #javatutorial #javacourse

public class Main {
public static void main(String[] args) {

if(isStudent){
}
else{
}

}
}

[BroCodez]

import java.util.Scanner;

public class Main {
public static void main(String[] args) {

Scanner scanner = new Scanner(System.in);

System.out.println("Enter your name: ");
String name = scanner.nextLine();

System.out.println("Enter your age: ");
int age = scanner.nextInt();

System.out.println("What is your gpa: ");
double gpa = scanner.nextDouble();

System.out.println("Are you a student? (true/false): ");
boolean isStudent = scanner.nextBoolean();

System.out.println("Hello " + name);
System.out.println("You are " + age + " years old");
System.out.println("Your gpa is: " + gpa);

if(isStudent){
System.out.println("You are enrolled in classes");
}
else{
System.out.println("You are NOT enrolled in classes");
}

scanner.close();
}
}

[icebot.]

String name = "Bro Code";
int gta = 6;
double pi = 3.14159;
char gender = 'M';
boolean isAdmin = true;

[larsintech]

I personally like to use a BufferedReader over a Scanner

[clipsworld-sxpv]

import java.util.Scanner;

public class Vid3
{
public static void main (String[] args)
{

Scanner scanner = new Scanner(System.in);

System.out.print("what is your number: ");
int number = scanner.nextInt();
scanner.nextLine();

System.out.print("hello what is your namme : ");
String name = scanner.nextLine();

System.out.print("what is your cgpa: ");
double grade = scanner.nextDouble();

System.out.print("are you a student?: ");
boolean answer = scanner.nextBoolean();

System.out.println("my name is " + name);
System.out.println("my number is "+ number);
System.out.println("my cgpa is " + grade );

if(answer)
{
System.out.print("i am a student ");
}
else
{
System.out.print("i am not a student");
}
scanner.close();

}

}

[Doctor_Hinky]

you can make ¹²³ with altGr and the numbers, is good to know if you not in win, cuz I use ubuntu and the num combinations never work for me (:

[giulioesposito]

I tried to do the rectangle exercise, but after i enter width and height, the output of the area is always 0.0. I have no clue about how to solve this problem

[nexograft]

How did you short cut the System outprintln();?

[MubeenKhalid-iq]

Why width, height and area=0
Can we run programme without putting them equal to zero???
I think thete is no need of width, height and area=0 at start

[kylescritten]

Today I went to a gloomy zoo.
In an exhibit, I saw a Joe Rogan.
Joe Rogan was muscular and vaping!
I was tired!

[ihabmidhat]

Mr Bo
I am ready this Java book and it have examples of entering data without a scanner
And I am not understanding that concept.
Here is the example

public static void main(String[] args) throws Exception {
double area, b, h;
 
//Data input - Prompt the user to enter values for base and height
System.out.print("Enter the length of base: ");
b =
System.out.print("Enter the length of height: ");
h =
 
//Data processing - Calculate the area of the rectangle
area = b * h;
 
//Results output - Display the result on user's screen
System.out.println("The area of the rectangle is " + area);
}

[GuruOfTheMoon]

for some reason in the last part of the video, the code just breaks when i try to put in decimal numbers, it works when i put in full numbers, i copied everything exactly like in the video, my code is:
import java.util.Scanner;


public class Main {
public static void main(String[] args) {
double height = 0;
double width = 0;
double area = 0;

Scanner scanner = new Scanner(System.in);

System.out.print("enter the width: ");
width = scanner.nextDouble();

System.out.print("enter the height: ");
height = scanner.nextDouble();

scanner.close();
}
}
the error is:
Exception in thread "main"
at
at
at
at Main.main(Main.java:13)

Process finished with exit code 1
i tried it 3x in a new project and it still didnt work, im really confused why (i havnt slept last night, so might be something obvious, but im trying my best)
(it shouldnt matter that height and width are swapped in the thing where the values are assigned, right?)