2#DeMoivresTheorem7Marks #Showthat (1 + i)^n + (1 - i)^n = 2^[(n + 2)/2] Cos (nπ/4)

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Senior Inter Maths2A DeMoivre's Theorem LAQ 7 Marks With Complete Solutions
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Show that (1 + i)^2n + (1 - i)^2n = 2^(n + 1)Cos (nπ/2)

Show that (1 + i)^n + (1 - i)^n = 2^[(n + 2)/2] Cos (nπ/4)

Show that (p + i q)^ 1/n - (p + i q)^ 1/n = 2 [(p^2 + q^2)^(1/2n)] Cos [(1/n)Tan^-1(q/p)]

If α, β are the roots of x^2 - 2x + 4 = 0 then show that α^n + β^n = 2^(n+1) Cos(nπ/3)

Show that (1 + Cos β + i Sin β)^n + (1 + Cos β - i Sin β)^n = 2^(n+1) Cos^n(β/2) Cos(nβ/2)

If Cos A + Cos B + Cos C = 0 = Sin A + Sin B + Sin C then show that Cos^2(A) + Cos^2(B) + Cos^2(C) = 3/2 = Sin^2(A) + Sin^2(B) + Sin^2(C)

If n is an integer and Z = CiS β then show that [Z^(2n) - 1] / [Z^(2n) + 1] = i Tan(nβ)

If Cos A + Cos B + Cos C = 0,
Sin A + Sin B + Sin C = 0 then show that
Cos 3A + Cos 3B + Cos 3C = 3Cos (A + B + C),
Sin 3A + Sin 3B + Sin 3C = 3Sin (A + B + C),
Cos (A + B) + Cos (B + C) + Cos (C + A) = 0

If x = Cos α + i Sin α,
y = Cos β + i Sin β then show that x^m y^n + 1 / x^m y^n = 2 Cos (mα + nβ), x^m y^n - 1 / x^m y^n = 2i Sin (mα + nβ)

Show that [1 + Sin (π/8) + i Cos (π/8) by 1 + Sin (π/8) - i Cos (π/8) ]^ (8/3) = -1
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Sir thamb nail lo unna question and e question different ga undhi thamb nail lo emo 2n+1 cos nπ/2 kani e kada emo cos nπ/4

nanidevalla
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(2+3i)+1/1-i solve this sir. I am confused

lakshmivarsha
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Naku thamb nail lo unna answer kavali sir please 🥺

nanidevalla
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Sir market lo.. Dare to success books available ha.. Sir

u.n
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Mrinal ananta 👏👏👏.Tq for saving us from online class test appreciate it man

NOVOLIGHT