Figure shows a square loop of side \( 0.5 \mathrm{~m} \) and resistance \( 10 \Omega \). The mag...

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Figure shows a square loop of side \( 0.5 \mathrm{~m} \) and resistance \( 10 \Omega \). The magnetic field has a magnitude \( B=1.0 \mathrm{~T} \). The work done in pulling the loop out of the field slowly and uniformly in \( 2.0 \mathrm{~s} \) is
(A) \( 3.125 \times 10^{-3} \mathrm{~J} \)
(B) \( 1.25 \times 10^{-2} \mathrm{~J} \)
(C) \( 6.25 \times 10^{-4} \mathrm{~J} \)
(D) \( 5.0 \times 10^{-4} \mathrm{~J} \)
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