A position dependent force F=(7–2x+3x^2)N acts on a small body of mass 2kg and displaces NEET 1994

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A position dependent force, F = (7 – 2x + 3x^2) N acts on a small body of mass 2 kg and displaces it from x = 0 to x = 5 m. The work done in joule is
(a) 135 (b) 270 (c) 35 (d) 70
(1994, 1992)

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In 2nd step, why it is divided with 2 and 3 respectively?

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