Electrolysis of water in a Hoffman apparatus

Shows the electrolysis of water using a Hoffman apparatus. The hydrogen is collected in a test tube and ignited. It makes the characteristic popping sound. The oxygen ignites a glowing wooden splint. The H:O ratio of 2:1 is clearly observed

[shaznindas]

Very well done, explained in a lucid manner, students can understand . Thank you

[princykaur]

Thank you, Sir! I'm going to use your video in my Year 10 class today.

[DeeAnnPaulReskBunnell]

Others have commented about why O and H don't bubble up in both tubes, which is something I wondered too, and others have speculated that water is not what was being split. Here's what I think I have figured out: a significant amount of gas to come out of solution and accumulate at a nucleation site in order to form a bubble. O and H are both formed at both electrodes, but one those ions is attracted to the nearby electrode where it accumulates while the other ion remains dissolved and travels through the connecting cross tube at the bottom toward the other electrode. Once it reaches the far electrode it accumulates enough to form bubbles there. There is probably not enough sulfuric acid to make the amount of gas that was in the tubes, and this demo can be done with other acids / electrolytes, which suggests the gasses are predominantly coming from the water.

[payaltiwari]

Reallly amazing 😊😊☺️☺️ happy from this video 😀😁

[omman]

thank you this is so cool because i am learning about it to

[Dezy]

So after taking oxygen he drops it to the side at 2:25 and opens another tube to demonstrate presence of oxygen. Cool scam. Also water is not H2O, what is happening is decomposition of the electrodes and the electrolyte. You can also do electrolysis without adding the electrolyte and you will see both electrodes decompose. Not water.

[lucasward]

he doesnt flinch at all when the explosive thingy happens

[johnnym]

If water is split into two parts then surely both gasses will be collected at each electrode. The sulphuric acid must be degrading into hydrogen on the positive electrode and oxygen on the negative electrode! Isn't this obvious Peter?

[waltright]

You didn't explain how the hydrogen and oxygen end up in separate tubes. 2H2O -> 2H2 + O2, this reaction would take place at both tubes, so both tubes would have both H2 and O2.

[이희준-yc]

May I ask the voltage and current for this experiment?