Newton's 2nd Law: Kinetic and Static Friction. Level 2, Example 2

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Newton's 2nd Law: Kinetic and Static Friction. Level 2, Example 2

Two boxes are slowly lowered down a ramp by pulling on a rope attached to the lower box, as in the figure. The boxes move together at 15.0 cm/s and the rope is parallel to the ramp. If the coefficients of friction are μk = 0.444 and μs = 0.800, find (a) the tension in the rope and (b) the magnitude and direction of the friction force on the upper box.
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Explanation was very straightforward and clear... Thank you @JHughesPhysics

profanityking
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you can define the positive direction to be any direction you like, right? but when I try this with up the ramp being the negative I get -f+(mgsin27.8°)=0. which gives me the right newtons but the friction force is pointing in the positive direction. which is wrong, right ?

joseocampo
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Why do you only draw 2 FBD? i drew both m2 and m1 and couldnt do it cuz my friction of m2 didnt match the friction that it was supposed to have on m1

Lazaruszzz
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Why the magnitude of the upperbox is not 140*0, 8 (coefficient of static friction) ?

YourAnimeMusicVideo
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why use cos instead of sine? need help pleasssseeee

trishaann