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The volume of O2 at STP required for complete combustion of 4g CH4 is: (answer in liters)
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Mole Concept question.
The following question is solved using unitary method.
answer:
4g CH4 = 11.2L O2
correction: at 1:37
- I meant 2 moles of oxygen atom. (not two oxygen atoms)
The following question is solved using unitary method.
answer:
4g CH4 = 11.2L O2
correction: at 1:37
- I meant 2 moles of oxygen atom. (not two oxygen atoms)
The volume of O2 at STP required for complete combustion of 4g CH4 is: (answer in liters)
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