Extension of GF(2) to GF(4)

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Addition and multiplication table of gf(2), gf(3), gf(5), gf(7).

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Couldn't understand it after the letcture. Now I kinda know what I am doing. Thanks a lot!

patrykpiotrpawewaaszek

why did you take the irreducible polynom to be zero? (when you did the mult. table). p(0)=1, p(1)=1 and GF(2).. so it doesnt make sense for me

מיכאלברקו

Very easy to understand with your explanation...

deepikasharma

Thanks for the video!
Is the table @5:00 constructed by dividing polynomials with rank=2 by the prime polynomial? Can you please elaborate on how the 0, 1, x, x+1 values are given? Thanks!

tomurkin

Sir, I am solving GF (2^3) problem.

For multiplicative inverse, I am not able to find like what value to add when multiplying x with x^2 + x? The answer is x^3 + x^2 but this is not an element of the field. What do to now?

Same problem with multiplying x with x^2 + x + 1

I understand the multiplication of x with x^2: x3

x3 + x + 1 = 0, hence x^3 = x+1

MaheshKumar-vipi

Can you say the set of conjugates for gf (4²) and minimal polynomials also.. kindly provide the image of the solution if possible

PriyaSharma-julb

Sir, can you tell how you got these reminder (0, 1, x, x+1) of equation x2 + x + 1?

Please assist

MaheshKumar-vipi

Nice.
1)on what based we take generator polynomial?
2)How we decide to substitute x=2 in additive table? ppls rply me sir

golmolenahisidhibaatein

Now I understood the logic. Thanks a lot

dushyantsingh

Sir i have exam pls clarify my doubt how did u fix the remainders when any equation is divisble by primitive polymial remainders will be 0, 1, x, x+1 plss respond soon

mansoorshaik

Please make a video on BCH codes and it's decoding

shubhambaunthiyal

Sir... how did you fix the prime polynomial ???

meeradeviramesh

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