Basic Trigonometry

Question:   (2sec theta+3 tan theta+5 sin theta -7cos theta+5)/(2tan theta+3 sec theta+5 cos theta +7sin theta+8)= <br>
(a)   &nbsp;&nbsp;&nbsp; tan (theta/2)   &nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;    
(b)  &nbsp;&nbsp;&nbsp;   cot (theta/2) &nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;       <br>
(c)  &nbsp;&nbsp;&nbsp;   sec (theta/2)  &nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;     
(d) &nbsp;&nbsp;&nbsp;    cosec (theta/2)     Â