Projectile Motion: Shooting a Basketball Problem

Physics Ninja looks at several projectile motion questions about shooting a basketball.

[eugeneallevato]

I would explain that the equation for the height is a parabola. So there are two solutions: one for going up and going down for the 10 ft mark. However, the velocity has a negative sign once starts going down. Once you calculate the time for 15 ft, you define the location. I guess, at least for me if you see the description of the trajectory as a parabola, it is easier to understand.

[koungmeng]

Glad you are back. Haven't seen you in 4 months xD

[lancepaschal]

How could the height of 3 meters and the acceleration due to gravity both be positive

[pauloopena]

May I ask why the Vy= Voy-gt is not Vy=Voy-gt because the Vo of the Vy would be zero cuz it's from the max height?

[jeromesmoral]

sir why did you used 9.81 m/s than 32.2 ft/s even though its feet?

[lincolninniss]

Hi, I worked out 3.56 m for the maximum height.

[connormann]

is the velocity you found for the final question the same as the final velocity?

[greerangeminecraft]

ITS NOT STRAIT forward to the point but its fine i learn something from it

[abbyberkenyi]

how would i solve this problem if my problem did not give me and initial height of ball but i have the initial velocity?

[armelasopjio]

Hello excuse me, is the velocity considere as a force? Otherwise I want to know how the movement on the horizontal direction is made.

[prathameshrumde]

hi sir
can we cal calculate initial velocity v by using formula R = v2 sin(2theta)/ g
R = 15 feet = 4.57 m
theta = 45 degree
if yes then im getting v as 6.69 m/s
pls clearify

[ribandrey]

Oh wait I have another question sir. In 12:59 you showed how to solve the time it takes for the ball to reach the rim, and actually we are doing our research now and we know the t or the time it takes for the ball to pass through the rim. So, can we simply calculate the initial velocity from there like:
Vo = L/((cos0)t) ?

[danielshamlian]

You lost me at 15:40

I don't understand how all the v sin thetas (I count four of them), only turn into v^2sin theta^2 -- it looks like either half of the equation would be that, but one just disappears. I can't base my studying on terms seemingly disappearing, so I can't use this to study, even if the answers are right. Thanks for trying.

[boscomerinoechevarria]

What if you don’t know the initial angle and what to find it

[nourmakhlouf]

in 10:56 you said the height was 3 ft... isnt it 7ft which is 2.13 m ?!

[ribandrey]

Hi Physics Ninja! It was a very informative video! However, I have a question. Is it possible to calculate the force exerted by the player (in your example) without the acceleration and final velocity of the ball given?

[Thewerwolf]

Last velocity value -3.18 is actually your value in ft/sec not m/s. Your value in m/s should be −0.99584 m/s. If you us this the angle should be actually -10.5 degree thus 10.5 down from the horizontal. Cheers and thanks you have fun content...

[tatemccune]

I don't think the maximum height is correct. how would it be less than the height of the basketball rim? I got 3.56 m for ymax

[cycrcvx]

you are wrong. sin 45 = cos45 that ridiculus.