Art of Problem Solving: 2019 AMC 10 A #24

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Art of Problem Solving's Richard Rusczyk solves the 2019 AMC 10 A #24.
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But the question says that s can't be p, Q and r, I dont understand how he substituted s=p

nidhiaggarwal
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i took basically the same soln but i didnt substitute s=p bc i thought it was restricted, had to monkey around with the variables a lot

dddd-txhv
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Woah... that's such a cool prob :) It has a nice, clean sol too.

jndd
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Intermediate algebra by aops makes this problem very free

RaZorasiangamer
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I think this is a harsh one because I couldn't think of the coefficient thing TT

chuyanwang
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This questions put to our semifinal test! Uh!

vsivsi
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the best math problems are always explained by quirkiest ppl 😂

kubyoindiya
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But it says s cannot be equal to p, q, r

zchenlic