Intro to GPU Programming

GPU programming with CUDA

[tuluwa]

among all the cuda videos I ve watched this one made the most sense to me

[asmaserajpour]

Amazing lecture. Helped me a for my final exam. Thank u soooo much. ❤️❤️❤️

[daylightnight]

It is like impossible power of computation! Beautiful beast!

[KristianDjukic]

This is very good video explanation about GPU computation

[jayacharankolla]

Amazing info! Love the way the data flow and execution is explained!

[TheAIEpiphany]

Great lecture thanks for sharing! Thanks for sharing an interesting piece of history on how "bug" concept came to be

[fire_nakamura]

Really enjoyed watching the vid, I've been learning computer architecture with nand2tetris and Digital Design and Computer Architecture by David Harris (Author), Sarah Harris (Author). I'm so happy to be able to understand the concepts he was talking about in this vid. Anyway thank you for the easy-for-beginner excellent content.

[ASCENDANTGAMERSAGE]

Cheers mate! Always love a good programming lecture. :)

[jsk]

Hi Tom, at 16:36, on line 19, you should fix the "float(i);" to "(float) i;" I'm assuming you're trying to cast the integer value to a floating point data type.

[ihgnmah]

15:20 Single Instruction Multiple Threads

[rm-]

Thank you so much for the video! Quite helpful. Appreciate it :D

[christokutrovsky]

Why did you need to use "float f" at time index 30:00 - why didn't you combine everything into 1 line of: "d_out[idx] = d_in[threadIdx.x] * d_in[threadIdx.x]" ? Is there a penalty for reading the thread index multiple times - or you did it just for clarity and explaining how the code works?

[BR-lxpy]

Could you have squared the d_in array in place? So d_in[idx] = d_in[idx] * d_in[idx]

[lakshyaagarwal]

How do you ensure that the threadID does not go out of bounds of the array? I could have 1000 threads right? But only have 60 elements in array to square.

[tsts]

Can you tell me what threads mean ? because I'm new to the GPU world😁

[NichtDu]

You could add timestamps

Great explanation! Thy