Vanishing sets define Zariski Topology on Affine Space.

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In this video, we are going to prove that the set of vanishing set defines Zariski topology on affine space.
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Maksym Zubkov

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Please watch: "Real Projective Space, n=1"
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Комментарии
Автор

Please continue this series! Your videos in this series are excellent!

sagnikbhattacharya
Автор

please continue this series on algebraic geometry. 👍

riadsouissi
Автор

I know you posted this a while ago, but on the off chance you see this, I was just wondering why we insist k is algebraically closed since you then use the real numbers in your example?

Many thanks for the videos by the way - they are very helpful!

ritchan
Автор

In this video in example m=3 where the vanishing set or sets are in some way making Zariski topology more course than the more familiar topology because these vanishing sets vanish? Thanks for the 2 related examples.

jeffreyhowarth