Adv Illustrations – Impulse by a String on a Moving Particle | System of Particles #42 for JEE Adv

Questions asked in JEE Advanced are based on critical thought processes rather than direct application of concepts. For preparation of JEE Advanced, students have to focus on problems based on multi concept applications.

Ashish Arora Sir has taken up a case of Impulse by a String on a Moving Particle from the chapter System of Particles which is important for select in IIT. System of Particles covered in Class 11 NCERT and is crucial in JEE preparation. These advanced illustrations cover all formulas and relevant solved examples from system of particles and are useful for making notes for IIT JEE preparation.

System of particles is one of the most critical sections of Mechanics in which questions are asked in JEE. This set of advanced illustrations covers questions on collision, compression in spring, center of mass, rocket ejection, elastic collision, coefficient of restitution, pendulum, potential energy, kinetic energy in collision cases, angle of divergence, bullet, displacement of center of mass, momentum, trolley cases, chain falling on a table. Questions have been asked on these concepts in previous years in JEE Mains, JEE Advanced and Olympiads.

#jeeadvance #jeephysics #pg4AdvIllustrations #sop4jee #systemofparticles

[srihariks]

Finally I got the solution for this problem with a proper explanation a lot sir

[carlosgiovanardi]

Dear sir, interesting question.
But I am facing the following doubt:
- initially we have total kinetic energy of 1/2 m u^2
- final kinetic energy is 1/2 m (3/16) u^2 + 1/2 m (7/16) u^2 = 1/2 m (10/16) u^2
Why? What happened? What am I missing?
I appreciate your comment.

[nathaliarodrigues]

sir why don't u reply to doubts..your videos are excellent though..Physics galaxy is pure gold

[Harshijain]

Why can't we use conservation of momentum equation instead of impulse? What change will it make?

[TheAakash]

Sir are physics galaxy solutions available or how to ask doubt of it

[priyanshkumar]

Sir why can't we apply Impulse - momentum equation for B in horizontal direction and write,
mu - Jcos 30° = mv2 ? where v2 is horizontal velocity of B ?

[Kirti-ubzy]

How we will calculate tension in this question

[nxpy]

Shouldn't kinetic energy be conserved in this case ?

[birupakhyapatro]

how to determine tension just after taut?

[swatisadhukhan]

Suppose intead of string we had light rod. Then also would there be impulse J due to rod?

[gouravgupta]

sir why we can't conserve energy of system???

[YashrajSinghRathour-jndf]

Why will they move with same velocity just after string is taunt i am not able to understand this.
Please some one explain this

[anushkatripathi]

sir why mg will not provide any impulse?