150+ Marks Guaranteed: DUAL NATURE OF RADIATION AND MATTER | Quick Revision 1 Shot | Physics for NEE

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[irumsyed]

33:50 : SLIDE 17 :option (c) MR⭐️ JINDABAAD🔥🔥.
34:22 : SLIDE 19 : option (A)
37:29 : SLIDE 21: 4 lamda
39:57 : SLIDE 23 : n=9 lambda
59:39 : SLIDE 33: option (c)
1:02:19 :SLIDE 35 : option (c)

[_priyans_]

50:40
Slide 29
The answer will be C-2.8
Agar 2√2 ka approx le rahe hai to 2×1.4 hoga na
Agar answer 3.8 lenge to uska square 3*3=9 se bhi jyada ho jayega but Hume √8 ka value nikal na hai

[aakashyadav-k]

Energy -- priyanka chopra madam. Here madam will help us to remember that it is momentum not power 😊😊

[gaurig]

SLIDE 17 :option (c)
34:22 : SLIDE 19 : option (A)
37:29 : SLIDE 21: 4 lamda
39:57 : SLIDE 23 : n=9 lambda
59:39 : SLIDE 33: option (c)
1:02:22 :SLIDE 35 : option (c)

[pratyushkumarpanda]

34:00 ans=C
34:28 ans=A
37:32 4lamda
39:52 6lamda
50:41 2.8 should be the answer 😊
50:56 ans=D
57:17 OP question
59:34 4 : 1
1:02:18 ans is lamda e>p>alpha

[Babaji]

Kis kis ko mahatandav cahiye mr sir ka vote?

[RookieGamerz-]

50:38 . The answer is C i think
Coz wavelength = 0.28/√V for proton. And 0.10/√V for alpha particle.
Divide and we get 2.8

[priyanshu_]

31:26 sir ne samjhaya sahi hai mark galat kr diya answer d hoga both correct, thank you master ji for this masterpiece lecture

[sameermalik.]

33:50 : SLIDE 17 :option (c)
34:22 : SLIDE 19 : option (A)
37:29 : SLIDE 21: 4 lamda
39:57 : SLIDE 23 : n=9 lambda
59:39 : SLIDE 33: option (c)
1:02:19 :SLIDE 35 : option (c) Slide 29
The answer will be C-2.8 thank u so much sir

[PrashantJalther]

Slide 29. Option 'C'= 2.8

2√2 = 2×1.41
= 2.8

[Milan-tadha]

Jo bhi is sal ko selection leke Mr sir ko Milne jayega vahi like karege

[richabharti]

34:25 slide 19 ans A
37:15 option 4
Slide 23 ans is 9
Slide 35 ans C
Slide 37 ans C

[AdarshSingh-qnpz]

SLIDE 17 :option (c) MR jordar
SLIDE 19 : option (A)
36:29 : SLIDE 21: 4 lamda
39:57 : SLIDE 23 : n=9 lambda
50:46 slide 29 answer c
50:56 Slide 30√mp/√me
55:03 slide 31 a
59:39 : SLIDE 33: option (c)

1:04:19 :SLIDE 37 : option (c)
H/√2mqev= 2500/50 =50v
Let mqev constant so =2√50
2× 1.71= 14.13

[MansiKumari-kl]

Sir jitna mehnat students ke liye syd he koi karega..thank u so much sir..🙏

[Unknownperson]

31:32 sir me galti se bataya ; statement 1 & 2 both correct

[sagarpanwarpranyodha]

31:00 sir stoping potential to intensity pr depending nhi hota na to fr wo power pr bhi kese depend hoga?

[Sumansourav-nbod]

Slide 23-9 lambda 40:01
49:38 slide29- 2.8
50:57 slide30- option d

[dishathavare]

31:26 both are correct.. stopping potential toh sirf frequency pe depend krta hai aur waha likha hai ki power pe depend nhi krta toh sahi hi hua na...

[akshitabhasin]

Amit sir: think without ink❌
MR sir: think without mind✔️

[satyabratakhilar]

31:25 Any one noticed that ki statement one is correct but sir ne incorrect bataya hai . ie, stopping potential doesn't depend upon the power of light source... 50:34 me ans option c hogaie-2.8