Integral of sin^3x

preview_player
Показать описание
This calculus video tutorial explains how to find the integral of sin^3x using the pythagorean identities of trigonometry and integration by u-substitution. You also need to be familiar with the basic power rule for integration and finding antiderivatives.

_______________________________________________________________________________________
_____________________________________________________________________________________
______________________________________________________________________________________
_____________________________________________________________________________________
_____________________________________________________________________________________
Рекомендации по теме
Комментарии
Автор

Thank you. I just pondered upon this integral for one hour but I didn't figure it out. Thank you once again so much.

ibrarkhan
Автор

The most slept on education channel on YouTube

amitavmostafa
Автор

The way I labored over this problem for like half an hour because I didn't realize you could pick cosx as u instead of cos^2x... 😶

pippinhart
Автор

I also had a lot of trouble with this problem. Once again, your explanations are brilliant and very helpful. Thank you very much..

jimcar
Автор

Found this from your sin^2(x) integral video. Another nice and succinct video👍

successthruknowledge
Автор

1:04 how do u know u is equal to cosx rather than sinx

KEQI-zvjm
Автор

We can use the formula sin3x = 3sinx-4sin³x, further get the value of sin³x

LogintoMaths
Автор

just a question why did the negative sign didnt effect constant ?

mezonei
Автор

why not take sin x =r then we have to integrate r^3 dr/cosx while integrating cosx come out as it it constant for what we are integrating

mamta
Автор

I am from hindi medium but I understand very.clearly thanks sir 🙏🏻 ❤ and your voice is soo sweet i like to hear your voice ❤😊

Vansh-tz
Автор

Can we also solve it
by using identity of sin3x ?

uditnarayan
Автор

Is there a method where you can use integration by parts?

Blaster
Автор

Thank you so much I have final tomorrow .

عبدالحميد-ظه
Автор

how can i put these informations in my head

iloveyouheeseung
Автор

My teacher made this more confusing then it had to be using some weird notation, thank you

Marshark
Автор

But surely you do not necessarily have to do substitution?

Instead of turning sin^2(x) into [1-cos^2(x)] you could use the double angle formula, where cos(2x) = cos^2(x) - sin^2(x) and thus with the use of sin^2(x) + cos^2(x) = 1 you can deduce that cos(2x)= 1 - 2sin^2(x).

Then you could rearrange for sin^2(x) = 1/2 - 1/2 cos(2x) and use that in the integral instead. I guess it is still a substitution per se but it doesn't require you to use the 'Integration by Substitution' method via the use of 'u'. I honestly prefer it this way, but I guess it depends on whatever suits you. Do you think this way is better? EDIT: Actually, I may have made life harder for myself, as you may have to do integration by parts later on anyway...

manishseeruthun
Автор

I dont understand why you have not added 1/2 here but you did when you expanded it before

christine.
Автор

why is the antiderivative for 1 u and not x?

ethanscott
Автор

I hate and love how the integral of sin³x is so much easier than sin²x.... No double angle needed, just turn it into (sinx - sinxcos²x) and from my experience with derivatives, i can immediately tell that since the function that has the power on it is multiplied with it's derivative, that i can just add onto the power and divide by it. Chain rule and it's reverse!
Meanwhile expanding sin²x into 1-cos²x doesn't help...

flightyavian
Автор

Cannot we imagine that u = sin(x)
????

thunder