Target Sum | Intermediate Coding Practice in Arrays | Lecture 16 | Java and DSA Foundation

Aren't arrays amazing? They enable us to solve complex problems conveniently.
Now, that you are familiar with the basics of arrays from the last class, Manvi mam will solve some tricky and frequently asked problems in exams and placements, based on the concept of target sum and array manipulation! Excited?!
Join the class to level up your logic building and understanding of arrays.

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Timestamps:
00:00 - Introduction
00:45 - Recap
02:08 - Today's Checklist
03:52 - Program to find the total number of pairs in the arrays whose sum is equal to the given value x
11:00 - Program to count the number of triplets whose sum is equal to the given value x
15:15 - Code
17:22 - Dry run
27:14 - Program to find a unique number in a given array
31:35 - Code
34:20 - Program to find the second-largest element in the given array
39:02 - code
45:44 - Dry run
49:10 - For an array of integers return the first value that is repeating in the array
52:25 - Code
55:43 - Dry run
1:01:20 - Summary of lecture

#Java #IntroductiontomethodsinJava #JavaMethods #PWskills #PhysicsWallah #Coding #LearnCoding #JavaArrays #HowToCode #ArraysinJava #2DArrays #IntroductiontoArray #ArrayinJava #Programming #Java #Programming

[sparsh-]

मैंम आपका सिखाने का तारिका बहुत अच्छा है... मैं आप से ये आशा करता हूँ कि जो आप लेक्चर के बाद इसी तरह प्रशन करवाऐ इस से समझने मे आसानी होती हैं

[modanwalpriti]

Hearty Thank you college wallah for providing us java lecture from basic to

[cs-rohitsahu]

For obtaining last elements that's repeated direction of loop will be opposite.

[sumittiwari]

mam a really grateful to you because i am afraid from this type of question but now i will solve without seeing you answer

[harshguleri]

For last repeating val :- we will not return the arr[i] inside if condition, we will store arr[i] in a variable(ans) and return outside the for loop. In starting we also have to initialize ans variable with -1.

[shaikhanis]

34:20 - Program to find the second-largest element in the given array
mam ap ka explanation bhohat hi achha hai but ye code thoda difficult hai or jyada bada bhi hai
or ek begginer ko nahi samj me ayenga

static int secLarge(int[] arr){
int largest = Integer.MIN_VALUE;
int sl = 0;
for (int i=0; i<arr.length; i++){
if(arr[i]>largest){
sl = largest;
largest = arr[i];
}
}
return sl;
}
i thik is se kam ho jana chahiye or ye assy bhi hai

[KamleshKumarYadav-fu]

thank u mam for giving us a very good course in free with outstanding explaination

[narutodihargo]

Timestamps:
00:00 - Introduction
00:45 - Recap
02:08 - Today's Checklist
03:52 - Program to find the total number of pairs in the arrays whose sum is equal to the given value x
11:00 - Program to count the number of triplets whose sum is equal to the given value x
15:15 - Code
17:22 - Dry run
27:14 - Program to find a unique number in a given array
31:35 - Code
34:20 - Program to find the second-largest element in the given array
39:02 - code
45:44 - Dry run
49:10 - For an array of integers return the first value that is repeating in the array
52:25 - Code
55:43 - Dry run
1:01:20 - Summary of lecture

[Sandeep_Yadav]

import java.util.Scanner;

public class LastReapeating {
static int LastRepeatingNumber(int[] array_1){
int n = array_1.length;
int lastrepeatingnumber = -1;

for (int i = 0; i < n; i++) {//first number
for (int j = i+1; j < n; j++) { //second number
if (array_1[i] == array_1[j]){ //found ans
lastrepeatingnumber = array_1[i];
}
}
}
return lastrepeatingnumber;
}

public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter array size");
int n = sc.nextInt();
int[] array = new int[n];

System.out.println("Enter " + n + " Elements");
for (int i = 0; i < n; i++) {
array[i] = sc.nextInt();
}

System.out.println("Last Repeating Number is : "+ LastRepeatingNumber(array));
}
}

[sunrisetravels-oo]

very clear and understanding lecture by u mam...really helpful thanks to college wallah

[chiragagrawal]

Mam from where we can practice coding questions topicwise...

[SangeetNagar-rd]

public class LastRepeatingValue {
public static int findLastRepeating(int[] arr) {
// Traverse the array from the end
for (int i = arr.length - 1; i >= 0; i--) {
for (int j = 0; j < i; j++) {
if (arr[i] == arr[j]) {
return arr[i]; // Return the last repeating value
}
}
}
return -1; // Return -1 if no repeating value is found
}

public static void main(String[] args) {
int[] array = {3, 5, 1, 3, 4, 5};
// Output: 5
}
}

[arvindkumarmishra]

For finding second max also we can use sort the array in ascending order and print the last second digit

[RanjeetYadav-zieh]

Notes and Assignments kaha se download kare . Ye wali link to work hi nahi kar rahi hai

[rakeshroy_]

in the finding unique element. We can also use break; statement instead of assigning the element to -1.

[distancelearning]

Mam aap typing ke time kuch short cut use karti Hai please aap short video ke through uske batye.
Like: From keyboard how to select specific row not all

[zeeshaxnn]

Mam I'm sorry for not consistent on your course
I'll watch it later
After completing my backlog

[girishpatil]

lastValueRepeat code

static int lastValueRepeat(int[] arr){
int valrepeat = -1;

for (int i = 0; i < arr.length; i++) {
for (int j = i+1; j < arr.length; j++) {
if(arr[i]==arr[j]){
valrepeat= arr[i];
}
}
}
return valrepeat;
}

[Gandhipatel-jjdz]

Someone help me! I can not access assignment. plese share link in the comment.

[fcanjalipatil]

Add more leetcode problem solving sessions mam ♥️