(ab)^-1=a^-1b^-1

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We will prove an identity from Micheal Spivak's Calculus

Problem: Ch1 #3.3
  1. Snell Bros. Math
  2. Math
  3. Multiplication
  4. Proof
  5. Spivak
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Автор

cant you use the property that (a^n)*(b^n)=(ab)^n ?

hollowshiningami
Автор

You say that ab is not zero because a and b are not zero, but I don't think this is clear until you do some of the later steps in the proof.

willnewman