From a disc of radius R and mass M, a circular hole of diameter R, whose rim passes through the cent

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From a disc of radius R and mass M, a circular hole of diameter R, whose rim passes through the Centre is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis, passing through the Centre?
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Wrong solution... correct answer is 13MR^2/32

macklinemoraes
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Are sir remove part me 1/2 kyo liya h circular hole ko disc suppose kyo kiya hai circular ring suppose nahi kar sakte kya sir ... confusion hi confusion 😵‍💫

Truth-nx
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Sir aapne minus se andar multiply he nahi kiya isliye galat ho gaya

yugwaghmode
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Last me glt ho gya but que kaise bnani hai smjh aa gya thankyou 😊

nisharaj
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Like matt do video delete Karo wrong solution hai bacche galat kar denge

MAYURESHMANE-irtr
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Galat ho gya sir..koi ni apki feelings samjh gye although

shreesh