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Find the cube root of z=-1+3i
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Another way of applying the nth root formula.
The nth root of a complex number:
[r(cosθ+i sinθ)]^(1/n)=r^(1/n) (cos(θ+2kπ)/n+i sin(θ+2kπ)/n), where k=0,1,2,…,n-1.
Solve for z^3=-1+3i.
The nth root of z^3=-1+3i.
The nth root of z^3+1-3i=0.
Welcome to join and feel free to raise/ask questions (if any) 🤗
#complexnumbers
The nth root of a complex number:
[r(cosθ+i sinθ)]^(1/n)=r^(1/n) (cos(θ+2kπ)/n+i sin(θ+2kπ)/n), where k=0,1,2,…,n-1.
Solve for z^3=-1+3i.
The nth root of z^3=-1+3i.
The nth root of z^3+1-3i=0.
Welcome to join and feel free to raise/ask questions (if any) 🤗
#complexnumbers
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