`2costheta=x+1/x`and `2cos phi=y+1/y` then (A)` x^n+1/(x^n)= 2 cos(n theta) n in Z` (B) `x/y+y/...

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+1/(x^my^n)= 2(cos mtheta +n phi), m,n in Z`
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but xy + 1/xy ko pehli term ke saath he kyu compare kiya, why not the 2nd term

dhruvsinghal
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sir if we assume x=e^(iota theta ) then the solution will be easy.😀😀

VivekSharma-skvp