JEE: Relations & Functions JPP - 1 | Unacademy JEE | IIT JEE Maths | Nishant Vora

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Unacademy JEE brings you yet another JEE Maths JPP session to prepare you for JEE Mains and JEE advanced. In this session, Nishant Vora Sir will be discussing JEE important topic “Relations & Functions”, he will cover the basic concepts of the chapter, important topics, and tips & tricks to remember the concepts and solve questions. Watch this video to know all about “Relations & Functions”

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[vibesoftheankushchoudhary]

sir you are great we feel proud that we are Nvians💕💕💕💕💕💕💖

[whitedevil]

Thanks for this jpp, you all are working so hard .I can't explain how you all are helping me

[pradipmsc]

क्या दूं गुरु-दक्षिणा मन ही मन मैं सोचूं, चुका न पाऊं ऋण मैं तेरा अगर जीवन भी अपना दे दूं। ...

❤❤

[arghojitsaha]

i have taken more than 2hrs in watching this session, but understood each and every steps and questions..thanks a lot sir😇

[suparnamandal]

I hv completed MSc in math and preparing for kvs pgt...your lectures help me a lot🙏

[pragya]

# GOR SE CHAMKA , best teaching style . Aaj ka class attend karke laga regular rahe to maths easy lagega .

[fighter]

The teaching methods of NV sir is on another level

[FunMan_]

*49:25** aapki smile bahut pyari hai 😀😀*

[harryjamespotter]

Please provide notes in description 🙏🙏🙏

[topicchaser]

I don't understand how can you make things so easy for students.

[khushiram]

my notes-
1) even degree polynomials ka graph upar se shuru hoke upar hi khatam ho jata hai
2) jaha pe bhi F`(slope)= negative vaha decreasing graph .... opposite applies for positive slope
3) try to observe that, , it's even or odd func

[juisonawane]

sir your teaching skills are great hats off to you sir

[ranaveer]

One of the best teacher in the world 🌍...❤️❤️❤️❤️
Lot of helpful

[sumankumarupadhyay]

Wow sir kya explain karte ho maja aa jata h love you🤟😘🤟😘🤟😘🤟😘❤

[acmelodies]

Last question discussed was literally osw❤️❤️❤️ lvl of question was 💥⚡🔥

[akash]

Answer to the homework
Graph of the function is wavy around the origin, kind of like x^3 (trust me I didnt use desmos)
Assuming f:R-->R, Function is
Onto
One-one
Odd
Range: (-infinity, +infinity)
Domain: (-infinity, +infinity)
Continuous: for all x € R
Differentiable: for all x € R ( This one was tricky)

Answer to second homework
a)1/4

[pankajpassionclasses]

❤ sir app bhut simple oe easy method se padhate h bhut mja आता h app kha se padhai kiye h

[kartikraj]

sir injective surjective ka alzebaric method bhi plz discuss kar dijye...