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maximum subsequence score leetcode 2542 python

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certainly! the "maximum subsequence score" problem is a well-known problem on leetcode (problem 2542). in this problem, you are given two lists of integers, `nums1` and `nums2`, both of the same length `n`. the goal is to select a subsequence from these lists that maximizes the score defined as the sum of the selected elements from `nums1` multiplied by the minimum of the selected elements from `nums2`.
problem statement
you need to maximize the score defined as:
\[ \text{score} = \text{sum of selected elements from } nums1 \times \text{min of selected elements from } nums2 \]
example
for example, given:
the maximum score can be obtained by selecting the elements from `nums1` corresponding to the largest values in `nums2`.
steps to solve the problem
1. **pair the arrays**: create pairs of values from `nums1` and `nums2`.
2. **sort by the second array**: sort these pairs based on the values from `nums2` in descending order. this will allow us to consider the largest possible minimums first.
3. **use a max heap**: as we iterate through the sorted pairs, we can use a max heap (or a priority queue) to keep track of the elements from `nums1` that we can select. this helps in maintaining the sum of the selected elements efficiently.
4. **calculate the score**: for each element from `nums2`, calculate the score based on the current minimum and the sum of the selected elements.
implementation
here is how you can implement this in python:
explanation of the code
1. **pairing and sorting**: we create pairs of `nums1[i]` and `nums2[i]` and sort them based on the values in `nums2` in descending order.
2. **using a heap**: we maintain a heap to keep track of the largest `k` elements from `nums1`.
3. **calculating scores**: we check if we have exactly `k` elements in our heap, and if so, we compute the score and keep track of the maximum score found.
complexity analysis
- **time complexity**: the sorting step takes \(o(n \log n)\), and maintaining the heap ta ...
#LeetCode #PythonCoding #windows
maximum subsequence score
LeetCode 2542
Python
dynamic programming
array manipulation
two pointers
sliding window
greedy algorithm
optimal substructure
subsequence
score calculation
algorithm efficiency
problem solving
coding interview
complexity analysis
problem statement
you need to maximize the score defined as:
\[ \text{score} = \text{sum of selected elements from } nums1 \times \text{min of selected elements from } nums2 \]
example
for example, given:
the maximum score can be obtained by selecting the elements from `nums1` corresponding to the largest values in `nums2`.
steps to solve the problem
1. **pair the arrays**: create pairs of values from `nums1` and `nums2`.
2. **sort by the second array**: sort these pairs based on the values from `nums2` in descending order. this will allow us to consider the largest possible minimums first.
3. **use a max heap**: as we iterate through the sorted pairs, we can use a max heap (or a priority queue) to keep track of the elements from `nums1` that we can select. this helps in maintaining the sum of the selected elements efficiently.
4. **calculate the score**: for each element from `nums2`, calculate the score based on the current minimum and the sum of the selected elements.
implementation
here is how you can implement this in python:
explanation of the code
1. **pairing and sorting**: we create pairs of `nums1[i]` and `nums2[i]` and sort them based on the values in `nums2` in descending order.
2. **using a heap**: we maintain a heap to keep track of the largest `k` elements from `nums1`.
3. **calculating scores**: we check if we have exactly `k` elements in our heap, and if so, we compute the score and keep track of the maximum score found.
complexity analysis
- **time complexity**: the sorting step takes \(o(n \log n)\), and maintaining the heap ta ...
#LeetCode #PythonCoding #windows
maximum subsequence score
LeetCode 2542
Python
dynamic programming
array manipulation
two pointers
sliding window
greedy algorithm
optimal substructure
subsequence
score calculation
algorithm efficiency
problem solving
coding interview
complexity analysis