How A sample of calcium carbonate \( \left(\mathrm{CaCO}_{3}\right)...

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How A sample of calcium carbonate \( \left(\mathrm{CaCO}_{3}\right) \) has the following percentage composition: \( \mathrm{Ca}=40 \% \);
\[
\mathrm{C}=12 \% ; \mathrm{O}=48 \%
\]
If the law of constant proportions is true, then the weight of calcium in \( 4 g \) of a sample of calcium carbonate obtained from another source will be
(1) \( 0.016 \mathrm{~g} \)
(2) \( 0.16 \mathrm{~g} \)
(3) \( 1.6 \mathrm{~g} \)
(4) \( 16 \mathrm{~g} \)
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Nice explanation ma'am thank you❤

AbhinavKumar-thxj