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Practice Problem 2.13 | Find V1&V2 and power dissipated in 3and20k ohm & power supply | Urdu & Hindi
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بسم الله الرحمن الرحيم
In this video you will learn about Practice Problem 2.13 .
Find: (a) V1 and V2,
(b) The power dissipated in the 3k ohm's and 20k ohm's resistors.
(c) The power supplied by the current source.
Use Series and Parallel & Current Division Rule (CDR) Techniques to Solve this problem.
Resistance in Series:
Req = R1 + R2 + R3 +............Rn
Resistance in parallel:
1/Req = 1/R1 + 1/R2 + 1/R3 +.........1/Rn
Current division Rule:
In Parallel , We know Current are Divided Separately. We Use CDR(Current Division Rule) to find Individual Current.
Formula:
i1 = [IT / (R1 + R2)] * R2
i2 = [IT / (R1 + R2)] * R1
I Hope You Have Enjoyed This Video :)
______________________________________________
What is series and parallel connection.
What is Voltage and Current Division Rule.
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_______________________________________________
#PracticeProblem2.13
#SolveSeriesandParallelCircuit
#PracticeProblem2.13CircuitAnalysis
#PracticeProblem2.13LinearCircuitAnalysis
#PracticeProblem2.13FundamentalofElectricCircuit
#PracticeProblem2.13DCNetworkAnalysis
#EngineerAbdulRaheem
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Find: (a) V1 and V2, The power dissipated in the 3k ohm's and 20k ohm's resistors, The power supplied by the current source, Practice Problem 2.13 Circuit Analysis, Practice Problem 2.13 Fundamental of Electric Circuit, Practice Problem 2.13 Linear Circuit Analysis, Alexander Practice Problem 2.13, Practice Problem 2.13 DC Network Analysis, Solve Series and Parallel Circuit,
How to Solve Any Series and Parallel Circuit Problem, resistances in Series and Parallel Combinations, Engineer Abdul Raheem, Electrical Engineering,
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وَيَسِّرْ لِي أمري
wa yassirli amri.
In this video you will learn about Practice Problem 2.13 .
Find: (a) V1 and V2,
(b) The power dissipated in the 3k ohm's and 20k ohm's resistors.
(c) The power supplied by the current source.
Use Series and Parallel & Current Division Rule (CDR) Techniques to Solve this problem.
Resistance in Series:
Req = R1 + R2 + R3 +............Rn
Resistance in parallel:
1/Req = 1/R1 + 1/R2 + 1/R3 +.........1/Rn
Current division Rule:
In Parallel , We know Current are Divided Separately. We Use CDR(Current Division Rule) to find Individual Current.
Formula:
i1 = [IT / (R1 + R2)] * R2
i2 = [IT / (R1 + R2)] * R1
I Hope You Have Enjoyed This Video :)
______________________________________________
What is series and parallel connection.
What is Voltage and Current Division Rule.
Practice Problem 2.5
Practice Problem 2.6
Practice Problem 2.7
Practice Problem 2.8
Practice Problem 2.9
Practice Problem 2.10
Practice Problem 2.11
Practice Problem 2.12
_______________________________________________
#PracticeProblem2.13
#SolveSeriesandParallelCircuit
#PracticeProblem2.13CircuitAnalysis
#PracticeProblem2.13LinearCircuitAnalysis
#PracticeProblem2.13FundamentalofElectricCircuit
#PracticeProblem2.13DCNetworkAnalysis
#EngineerAbdulRaheem
If You Like The Video Please Share It And Subscribe My channel. :)
__________________________________________________________________
TAGS:
Find: (a) V1 and V2, The power dissipated in the 3k ohm's and 20k ohm's resistors, The power supplied by the current source, Practice Problem 2.13 Circuit Analysis, Practice Problem 2.13 Fundamental of Electric Circuit, Practice Problem 2.13 Linear Circuit Analysis, Alexander Practice Problem 2.13, Practice Problem 2.13 DC Network Analysis, Solve Series and Parallel Circuit,
How to Solve Any Series and Parallel Circuit Problem, resistances in Series and Parallel Combinations, Engineer Abdul Raheem, Electrical Engineering,
🔵 FOLLOW ME ON INSTAGRAM :
🔵 FOLLOW ME ON facebook :
🔵 FOLLOW ME ON faceboook page :
Thanks
وَيَسِّرْ لِي أمري
wa yassirli amri.
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