Calculating MOLARITY from pH!

preview_player
Показать описание

Рекомендации по теме
Комментарии
Автор

Hi Everyone! Thanks for watching the video. Slight error at the end as pointed out by @DavidWells. In the last step, you need to divide the total moles of HCL (0.300mol) by the volume of stock soln (0.025L) - [0.300mol/0.025L=12M].

Hope that helps and remember to please subscribe!

chardomulholland
Автор

I think the last step was wrong, you would be dividing the total moles of HCl by the volume in liters of the stock solution (.025 L) to get the correct answer of 12 M.

davidwells
Автор

Thx...you solved one of the my exam`s question... I subscribed you

_allien_
Автор

Could've used the CV1=CV2 but oh well. Thanks!

notjoud
Автор

what should i do if the only given information is the substance and the pH?

yukiwinsatlife