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Let \( y=y(x) \) be the solution curve of the differential \( P \) ...
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Let \( y=y(x) \) be the solution curve of the differential
\( P \) equation, \( \left(y^{2}-x\right) \frac{d y}{d x}=1 \), satisfying \( y(0)=1 \). This curve
W. intersects the \( \mathrm{x} \)-axis at a point whose abscissa is:
(a) \( 2-\mathrm{e} \)
[JEE Main-2020 (January)]
(c) \( -\mathrm{e} \)
(b) \( 2+\mathrm{e} \)
\( P \) equation, \( \left(y^{2}-x\right) \frac{d y}{d x}=1 \), satisfying \( y(0)=1 \). This curve
W. intersects the \( \mathrm{x} \)-axis at a point whose abscissa is:
(a) \( 2-\mathrm{e} \)
[JEE Main-2020 (January)]
(c) \( -\mathrm{e} \)
(b) \( 2+\mathrm{e} \)