Differentiation of Trigonometric functions 1

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This video teaches the Differentiation of trigonometric functions of sine, cosine, tangent, secant, cosecant, cotangent and their combination etc.

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Bro, you are busy labouring in the social media teaching people who haven't paid anything to you with very smart explanation. The kind of a person you are brother is really unique. I have been just gambling with differentiation but after watching your video, truly I gained a lot of change. Am even left with a debt in my life of what to appreciate you with! I pray may the almighty give you more years and years to change the generations to come..

Olilaceaser
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I have my finals in less than 2wks and was lagging in calculus
I just watched the whole differentiation playlist
Thank you so much
God bless you

drillcity
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Thankyou so much..i have a calculus exam in a months time and i now feel ready for the differentiation questions .you have dissected this so well.blesssings

miriamwanjuki
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For the last differentiation, we can also proceed this way:
We have Cos³(2x+5). The differentiation goes:
(Cos³(2x+5))'. We know that (Cos(ax))'= -Sin(ax), and the derivative or differentiation of a powered equation is (x^n)'=nx'x^n-1(for example So:
-6Sin(2x+5)Cos²(2x+5). You are great and you explain very well, keep up👏. I don't know much about probabilities, I would really appreciate some lessons about it.

relaxingnoisewhite
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My name is precious 💕, What this man is working is Very Leaning and important to Understand.GOD bless you sir❤.

faithfolorunsho
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bro your God sent, thanks for the good work❤❤❤❤

UwitekaHodari
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This man is too much.... It's quite understandable, I appreciate you so much sire.

fodaybindijohnmaada
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May the almighty God bless you abundantly

Tabitha-nw
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Please do a video on tangents and normals, minima and maxima and parametric equations

drillcity
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Thank you sir you really make life easier ❤ from Nigeria

JoyBature-fi
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God bless u sir lots of love from Malawi

angellakachingwe
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Your explanation is very easy to understand. Good work

ifidonezomo
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Thank you very much sir for the amazing class..

ramadanbarrie
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Much appreciation, Am following from East Africa.

bigbong
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thanks a lot btw... can u do a video about differentiation of hyperbolic functions and inverse hyperbolic functions?

ScottAnthony-rhjd
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The method is good but there's a shortcut that I would recommend. We know by formulas that:
(Sinu)'=(u)'×Cosu therefore, if, for example we want to differentiate y=Sin(2+e^5x), we'll have:
y'=(Sin(2+e^5x)'
Say u=2+e^5x, then Sin(2+e^5x)=Sinu, therefore the differentiation goes:
(Sinu)'=(u)'×Cosu, and (u)'=(2+e^5x)'=5e^5x, therefore (u)'×Cosu=(5e^5x)×Cos(2+e^5x) => y'=(5e^5x)Cos(2+e^5x). But I think your method is faster😅

relaxingnoisewhite
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Pls in the e^5x when U differentiated it in example 3 why didn't the power reduce to 4x why did it still remain as 5x

OkoroDaisy
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Nice job done sir
Please ga you teah on how the dervatives of those trigonometrical ratios were obtained

akachukwuorujekwe
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Can you please help me with differentiation of Determinant

wanwodsciencedepartment
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Sr i have problem in this function y= x³sin2xcos4x how to solve this

renomalou