Java Bangla Tutorials 63 : How to check an Armstrong number (Theory)

➡️ In this video, I will show how to check whether a number is an Armstrong.
⭐️ Video Contents ⭐️
⌨️ (00:00) Intro
⌨️ (00:12) Armstrong number
⌨️ (06:25) outro

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#java #anisul_islam #java_bangla_tutorial #web_development #bangla_web_development #andorid #javaprogramming #javatutorial #bangla_tutorial #java_anisul_islam

[uttaraclublimited]

Dear Brother, you are really Great Teacher.i am very impressed to see you lesson.God bless you.

[fariahossainchowdhury]

Amr CSE subject ta ami book er cheya apnar video dekha beshi shikhechi.
R bujhteo kono problem hoyni alhamdulillah.
Thanks Sir.

[yusufsarker]

onk valo vabe bujhan apni sir, thanks

[knowledgeboy]

Armstrong number somporke jantam na aage
thanks sir

[yasirarafat]

Sir, your video is Thank you Sir for this video ❤️

[newstime]

thanks via, theory dekle buja jai, prectical r dekte hoina

[tanim]

apni tutorial bananor jonne kon software ta use kore ?
software ta ki open source?
nam and download link ta pele valo hoto ..thanks a lot

[m_tipsbd]

vai..apni kon unversity theke cse korchen..

[souravdhar]

I tried the code by myself and thought why it should be limited just for 3digits number only!!..so, took a mentos and modified the code which will take any length of digit and determine whether Armstrong or not.. here is my code..

public class Armstrong_number {
public static void main(String[] args) {
Scanner input= new Scanner(System.in);
int num, r, count = 0;
int temp, temp1;
int sum=0;
System.out.print("Enter a positive number: ");
num= input.nextInt();
temp=num;
temp1 = num;

while(temp!=0)
{
count++;
temp= temp/10;
}

while(temp1!=0)
{
r= temp1%10;
sum= (int) (sum+(Math.pow(r, count)));
temp1= temp1/10;
}
if(num==sum)
{
System.out.println(num+" is a armstrong number.");
}
else
{
System.out.println(num+" is not a armstrong number.");

}

}
}

[a.n_gaming]

sir, SUM= SUM+ pow(R, 3) evabe likhle ki problem hobe?

[fazlerabbi]

অনেক সুন্দর হইছে ভাইয়া❤️

কিন্তু আমার প্রশ্ন এখানে তো তিন ডিজিটের দেখানো হইছে

যদি ইউজার তার ইচ্ছে মতো নাম্বার দেয় তাহলে কি ভাবে করবো?

[ashrafulmomenshuvo]

vaya c video lesson e Java er onk golo tutorial ace
ager kico lesson pacci na
kindly ektu dekben.

[sajibbosenewton]

Theory part gulor sound sona jasce na, jemon 43, 45, 47

[adulladahalrifat]

eta only 3 digit er number r jnne, , jekono digit r number er jnne akta code paisi
#include<stdio.h>
#include<math.h>
int main (){
int num, originalNum, remainder, n = 0;
float result = 0.0;

printf("Enter an integer: ");
scanf("%d", &num);

originalNum = num;

// store the number of digits of num in n
for (originalNum = num; originalNum != 0; ++n) {
originalNum /= 10;
}

for (originalNum = num; originalNum != 0; originalNum /= 10) {
remainder = originalNum % 10;

// store the sum of the power of individual digits in result
result += pow(remainder, n);
}

// if num is equal to result, the number is an Armstrong number
if ((int)result == num)
printf("%d is an Armstrong number.", num);
else
printf("%d is not an Armstrong number.", num);
return 0;
}

[m_tipsbd]

amio cse korte chai....eita korle job opportunity kemon

[mdshejan]

onk valo vabe bujhan apni sir, thanks