Cross Retinoscopy just in 4 Simple Steps

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#retinoscopy #crossretinoscopy #optometry
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Sir i think final prescreption power is [ +1.50/+1.00 # 90' ]

kaushalsen
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In this optical cross you consider horizontal meridian as Spherical meridian. You explained that we can take any meridian as Spherical meridian. So in this optical cross if we consider vertical meridian as Spherical meridian the final optical cross power will be +1.50/+1.00×90° right?

rajeshtripura
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sir myopia less than WD in projection stage of retinoscopy then what will be the movement ? with or against?

adnannoor
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For calculating cyndrical we need to subtract 180degree power from 90 degree??

shalusingh-kw
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How to find the final power in refraction recept. R.E +1.00-2.50, 130&L.E +1.00+2.25, 10 please tell me

SathwikM-sizy
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Vertical 4 neutralize h or horizontal 3 h pr cross me wrong kio kr diya 🤔

iqra_life
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How to find pesoduphakia using retinoscopy reflex

vaishaliganesan
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Why is the degree of working distance always subtracted from the value of the correction lens derived from the retinoscope device? Can I prove this with physical proof and a mathematical formula? I need an answer please 🙏

conanr.
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Why did you subtract working distance from cylinder also????

batsonplexus
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Sir I have a doubt .
Horizontal meridian is -3.00, vertical meridian is+2.00 then how to calculate the refractive error

Kusuma
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If vertical meridian is 90'
Then i think final number is
+150sph/+100cyl 180'

KumarSD