Prove that cos^8A - sin^8A = (1 - 2cos²A)(1 - 2sin²A cos²A)

preview_player
Показать описание
Prove that cos^8A - sin^8A = (1 - 2cos²A)(1 - 2sin²A cos²A)
Prove that sin^8A - cos^8A = (sin^2A - cos^2A)(1 - 2sin^2Acos^2A)
Prove that sin^8a-cos^8a=(1-2cos^2a)(1-2sin^2acos^2a)
prove that cos^8A - sin^8A = (cos^2A - sin^2A)(1-2sin^2A cos^2A)
prove that cos^8A - sin^8A = (2sin^2A - 1)(1-2sin^2A cos^2A)
#math #trigonometry
  1. Pace Edu.
Рекомендации по теме
Prove:𝐶𝑜𝑠^8 𝐴+𝑆𝑖𝑛^8 𝐴= 0:07:38

Prove:𝐶𝑜𝑠^8 𝐴+𝑆𝑖𝑛^8 𝐴= 1− 𝑠𝑖𝑛^2 2𝐴+1/2 𝑠𝑖𝑛^4 2𝐴

Prove that cos^8A 0:07:13

Prove that cos^8A - sin^8A = (1 - 2cos²A)(1 - 2sin²A cos²A)

76Trigonometry Show that 0:08:40

76Trigonometry Show that Cos A Cos 2A Cos 4A Cos 8A = Sin 16A / 16Sin A

`sin^8A-cos^8A=(sin^2A-cos^2A)(1-2sin^2Acos^2A)` 0:03:20

`sin^8A-cos^8A=(sin^2A-cos^2A)(1-2sin^2Acos^2A)`

Prove the following 0:05:40

Prove the following identities: `cos^8A-sin^8A=(1-2sin^2Acos^2A)(1-2sin^2A)`

Prove that (Sin^8A 0:04:37

Prove that (Sin^8A -Cos^8A) = (Sin^2A - Cos^2A)(1 - 2Sin^2ACos^2A)

Prove that:cos^8A+sin^8A=1-sin^2 2A+1/8sin^4 0:11:10

Prove that:cos^8A+sin^8A=1-sin^2 2A+1/8sin^4 2A

Show that : 0:02:40

Show that : `sin^8 A-cos^8 A = (sin^2 A - cos^2 A) (1-2 sin^2 A*cos^2 A)`

Show that: `sin^8A-cos^8A=(sin^2A-cos^2A)(1-2sin^2Acos^2A)` 0:03:46

Show that: `sin^8A-cos^8A=(sin^2A-cos^2A)(1-2sin^2Acos^2A)`

sin^8A-cos^8A=(1-2sin^2A.cos^2A)(sin^2A-cos^2A) || class 0:00:59

sin^8A-cos^8A=(1-2sin^2A.cos^2A)(sin^2A-cos^2A) || class -XI ||

The value of 0:03:48

The value of `cos^8A-sin^8A` where `A=pi/12` radian

Prove that cos 0:03:43

Prove that cos A cos 2 A cos 4 A cos 8 A=sin 16 A/16 sin A.

sec8theta-1/sec4theta-1=tan8theta/tan2theta l Trigonometry 0:03:46

sec8theta-1/sec4theta-1=tan8theta/tan2theta l Trigonometry Hots 🔥 11th Maths

`\ t h 0:04:02

`\ t h a t : :(cos8Acos5A-cos12 Acos9A)/(sin8Acos5A+cos12 Asin9A)=tan4A`

Cos A Cos 0:12:18

Cos A Cos 2A Cos 4A Cos 8A = Sin 16A / 16 Sin A & hence deduce that Cos 2pi/15 Cos ...=1/16 @EAG

9. Maths Trigonometry 0:03:59

9. Maths Trigonometry Problem Prove that (sec 8A - 1) upon (sec 4A-1) = tan 8A upon tan 2A

Prove that : 0:08:20

Prove that : (Sec 8A - 1) / (Sec 4A - 1) = Tan 8A / Tan 2A | trigonometry | Class 10 trigonometry |

All exam Based 0:02:01

All exam Based Q//If sin^8A – cos^8A = 1200 then find the value of (4 – 8cos^2A)(1-2sin^2A.cos^2A)...

Prove: Sec8A-1/ sec4A-1= 0:04:05

Prove: Sec8A-1/ sec4A-1= tan8A/ tan2A

Trigonometry XI Grade: 0:06:19

Trigonometry XI Grade: Prove that (Sec8A - 1)/( Sec 4A - 1) = Tan 8A / Tan 2A

Prove that: tan 0:08:17

Prove that: tan A + 2tan 2A + 4tan 4A + 8cot 8A = cot A

Prove that: sin⁴ 0:05:48

Prove that: sin⁴ A = 3/8 - 1/2 cos 2A + 1/8 cos 4A

`sin^2(pi/8+A/2)-sin^2(pi/8-A/2)=1/(sqrt(2))sinA` 0:03:07

`sin^2(pi/8+A/2)-sin^2(pi/8-A/2)=1/(sqrt(2))sinA`

Intermediate First year 0:08:50

Intermediate First year transformation of trigonometric first year problems explained in Telugu