Understanding why Integer.parseInt throws a NumberFormatException for the input string '''827'''

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The Problem: Input String """827"""

Consider the following code snippet:

[[See Video to Reveal this Text or Code Snippet]]

Explanation

The input string """827""" contains double quotation marks, which are invalid characters in the context of parsing an integer. When Java encounters these characters while parsing, it cannot interpret them as part of a valid integer representation, leading to the NumberFormatException.

Solution

To avoid this exception, ensure that the input string contains only valid characters that can be interpreted as an integer. For instance, removing the double quotation marks:

[[See Video to Reveal this Text or Code Snippet]]

In scenarios where the input string might have extra characters, you can sanitize the string to remove the invalid characters before attempting to parse it:

[[See Video to Reveal this Text or Code Snippet]]

Conclusion