Show that the relation R in the set 𝐑 of real numbers, defined as R={(a, b): a ≤ b^2} is neither...

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Show that the relation R in the set 𝐑 of real numbers, defined as R={(a, b): a ≤ b^2} is neither reflexive nor symmetric nor transitive.
Reflexive: a=1/2 (1/2, 1/2) ∈ R
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Sir jaha aap reflexive prove kiye hna=1/2 maan k what if ham a= 1 maan le tab tho satisfy ho raha hn

anand-
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Sir if we take 2, 2 in ref we get as this relation is

r.kpandeypandey
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It's easy way to understand best platform for education is pw😊❤

aravindhullur