filmov
tv
`cos (cos^-1 cos((8pi)/7) +tan^-1 tan(8pi/7))` has the value equal to -
Показать описание
0:02:22
`cos (cos^-1 cos((8pi)/7) +tan^-1 tan(8pi/7))` has the value equal to -
0:01:38
Find the value of Cos{cos ^-1cos(8pi/7) +tan ^-1tan(8pi/7)}
0:01:50
Evaluating the composition of Functions
0:05:50
Cos(2pi/7)+Cos(4pi/7)+Cos(8pi/7) = (-1/2)
![sin^-1[sin(9pi/8)]](https://i.ytimg.com/vi/CBO1HIAHLe0/hqdefault.jpg)
0:01:10
sin^-1[sin(9pi/8)]
0:01:49
Cos Inverse Cos (13π/6)// Cos Inverse Cos 7 pi by 6//Cos Inverse Cos 5π/4 //tan Inverse tan (8π/7)//...
0:02:12
cos^-1(cos(15pi/7))
0:01:28
cos^-1(cos(7pi/6))
0:00:10
prove that 1+cos(2Pi/7)cos(5pi/7)=sin(2pi/7)sin(5pi/7)
0:07:51
Cos (2 pi/7) Cos (4 pi/7) Cos (8 pi/7) = 1/8 @EAG
0:06:04
[Cos2pie/7 -sin2pie/7 Sin2pie/7 cos2pie/7]^k = I find K
0:05:27
Find Exact Value of cos 8pi by 12 Compound Angle Trigonometry
0:13:28
Prove that Cos2π/7.Cos4π/7.Cos8π/7=1/8 ||C.S Method ||in Telugu||intermediate maths1A ||
0:13:28
Prove that: cos 2pi/7 + cos 4pi/7 + cos 8pi/7 = -1/2
0:00:37
sin^-1(sin(-3pi/7))
0:05:10
1+cos 2π/7 . cos5π/7 = sin 2π/7 . sin5π/7 || trigonometry || SEE MATH SOLUTION
0:03:18
Solving cos(π/7) + cos(3π/7) + cos(5π/7) Using Trigonometry
0:11:40
Prove that: cos π/7. cos 2π/7. cos 3π/7 = 1/8
0:01:57
Prove that: `cospi/7cos(2pi)/7cos(4pi)/7=-1/8,`
0:00:57
The value of cos^2〖π/16+cos^2〖3π/16+cos^2〖5π/16+cos^2〖7π/16〗 〗 〗 〗...👇...
0:07:34
Graph Radians Step by Step
0:06:22
Geometry : calculate of cos(pi/7)cos(4pi/7)cos(5pi/7)
0:00:47
#BSEB_2020 || #Inverse_trigonometry ||cot(tan–¹x +cot–¹x) = ? || #CBSE || #Class12th || #math
0:02:57
Ex2.2 19. cos-1(cos7π/6) || cos inverse cos 7pi by 6 || class 12 exercise 2.2 question 19
Комментарии