0580/42 February/March 2018 Marking Scheme (MS)

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IGCSE Ordinary Level (O-Level)

0580/42 February/March 2018 Paper 4 (Extended)

Links to download Marking Scheme & Question Paper

Question Paper:

Marking Scheme:

Audio:
Intro Music by Andrew Applepie

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Hi guys attached is a link to the correction compilation identified by the community!
Quick Links to specific question
Q1
(a)
i. 1:14
ii. 1:45
(b) 2:18
(c) 3:36 *MISTAKE ALERT*

Q2
(a) 4:24
(b)
i. 5:47
ii. 6:57

Q3
(a) 7:59
(b) 10:06
(c) 10:13 inequalities sign need to be included less than equal 0.225 & more than equal to 2.5
(d) *Solution combined*
i. 10:58
ii. 10:58

Q4
(a) 13:13
(b)
i. 13:28
ii. 13:50
(c) 14:50
(d) 15:40

Q5
(a)
i. 16:36
ii. 18:47
(b) 19:53

Q6
(a) 20:43
(b) 22:31 *MISTAKE ALERT*
(c) 22:41

Q7
(a)
i. 23:23
ii. 23:43
(b) 24:47
(c) 25:59
(d)
i. 26:09
ii. 26:40 *MISTAKE ALERT*
iii. 27:48
iv. 28:40

Q8
(a) 29:18
(b)
i. 30:33
ii. 31:46

Q9
(a) 32:54
(b) 33:19
(c) *Remember to add a bracket to all the answer below*
i. 33:54
ii. 34:20
iii. 34:59
iv. 36:04

Q10
(a) 37:20
(b)
i. 28:08 *MISTAKE ALERT*
ii. 38:27
iii. 38:50

Q11
(a) 41:32
(b)
i. 39:27
ii. 40:44
(c) 41:09
(d)
i. 42:03
ii. 42:40

DMathAcademy
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in question 2 b ii] we shall first find the perimeter of the arc

1--- 90\360 *2*8*pie
this equals to 4 pie cm
2---- nextly we should subtract the 2 radii since we just want the perimeter of the shaded segment this equals to 4 pie---16 cm3---- lastly we shall add the length of AD since we are finding the perimeter and in the first step we only got the perimeter of the curved surface4-- lastly combine all values4 pie-16cm+(square root of 128 )=7.88079113 cm to 3.s.f this equals to 7.88 cm

neerukashyap
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Isn't question 1C supposed to be upper bound divided by lower bound???then the answer is 70

jthatguy
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Good work trying to help others solve the past papers but sadly some of your answers are wrong

bijimathew
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Hey dude, Nice video
But,
Question 7d(ii) is wrong and the answer is 38.


Nice work overall, keep it up

bronxslayea
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