Perimeter and Area | ONE SHOT | Chapter 9 | Class 7 | BYJU'S

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[Editzx_]

Homework
Area=πr²
Area=22/7×20²
Area=8800/7
Area=1257.14

Area of 2nd circle=πr²
Area=22/7×48²
Area=22/7×2304
Area=50688/7
Area= 7241.14

3rd circle = area of 1st and 2nd circle

1257.14+7241.14
=8498.28

Hence 8498.28 answeris

[JhumaBanerjee-zsqi]

I love it when ma 'am says " Samajh mein aaya mere bachon ko". It literally feels like my mom is telling me❤

[HexalightGaming]

Thank you for teaching mam😊😊❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤..Pls

[Rizviya-fatma]

Thankyou mam for this wonderful Explanation 🙂👏👏✨🤗 Crystal clear 😊👍👍👍👍👍👍👍❤❤😊❤😊❤❤ Thankyou so much

[Rizviya-fatma]

Thankyou mam for this wonderful Session 👍👍 Crystal clear 😊😊😊😊😊😊❤❤😊❤

[foodiegirl]

🎀Thank you so much dear mam 😊
All chapter's is crystal 🔮✨ clear 💫
Again thank you so much ☺️💓
Lot's of love

[SaraRs-nodd]

given,
radius of 1st circle = r = 20m
radius of 2nd circle = r' = 48m

as we know the formula for area of a circle= Πr², where Π = 22/7

so area of 1st circle
= Πr²
= 22/7 × (20)²
= 22/7 × 20 × 20
= 8800/7 m²

area of 2nd circle
= Π(r')²
= 22/7 × (48)²
= 22/7 × 48 × 48
= 50688/7 m²

sum of area of both the circles
= 8800/7 + 50688/7
= 59488/7 m²

according to the question,
let the radius of the 3rd circle = r"
then,

area of the 3rd circle = 59488/7

=> Π(r")² = 59488/7

=> 22/7 × (r")² = 59488/7

=> (r")² = 59488/7 × 7/22

=> (r")² = 2704

=> r" = √2704
= 52m


Hence the radius of the new circle is 52m
This done by sara

[somyayadav]

Mam apne sahi baat boli mene activity kr ke dekhi❤

[minakshisharma]

Thanks for teaching mam😊😊 .you explain very nicely❤❤❤

[Disha_]

Homework solution..
Radius of the 1st circle=20m
So area =πr1²
=22/7×20×20
=8800/7
=1257.14m²
Area of 2nd circle=πr2²
22/7×48×48
=50688/7
=7241.14m²
Total area= 1257.14+7241.14
=8498.28
πr3²=8498.28
r3²=8498.28×7/22
r3²=59488/22
r3² =2704
r3² =√2704
r3=52 m
This session was amazing😍😊
Thank you arsh ma'am❤😊

[dancewithpari]

Mam doubt
Actually at 13:00 you made the height at the outer side
So if we want
Can we make the height inside the figure also?
Or it is compulsory to make the height outside the figure?

[SureshKumar-nmjx]

Hi, Arsh mam this class is the best class ever after this class the concept is very clear for me. I am Mihir . Homework Question: The required radius of the third circle is 52m.

[Reenaa-jy]

Today's homework answer
Let A1 = the area of the circle whose radius is 20 m [given] A2 = the area of the circle whose radius is 48 m [given] Now we have to find the radius of third circle such that whose area is equal to the sum of areas of two fields. Hence, A3 = A1 + A2 ⇒ πr2 = π(20)2 + π(48)2 ⇒ πr2 = π[(20)2 + (48)2] ⇒ r2 = 400 + 2304 ⇒ r = 52 m Therefore radius = 52 m.

[neelamchhabra]

Thank you so much for this wonderful understanding ❤❤

[sigmagaming]

Homework answer is 52 m .
Mam the session was entertaining, informative, useful and interesting ❤️❤️.
We want more such sessions.

[deepak_gaming]

Today's homework answer
Let A1 = the area of the circle whose radius is 20 m [given] A2 = the area of the circle whose radius is 48 m [given] Now we have to find the radius of third circle such that whose area is equal to the sum of areas of two fields. Hence, A3 = A1 + A2 ⇒ πr2 = π(20)2 + π(48)2 ⇒ πr2 = π[(20)2 + (48)2] ⇒ r2 = 400 + 2304 ⇒ r = 52 m Therefore radius = 52 m.
name - deepak kumar

[neharamesh]

Mam es Bahut achi class thi..❤loved your class 😊

[RPGisCOOL]

Only 742 love sweets, if including me that's 743!!🤣🤣

[neelampandey]

Ma'am homework answer please check kar Lijiye

1 field
Area 400
2 field
Area 2304 and
3 field is
= 400+2304
= 2704
Square root of √2704
=52 m is ans
My name is Nishtha Pandey
Please mam check my answer



Sorry ma'am late ans comment ke liya

[radhikagupta]

Mam you are the bbeesssttt teacher🎉🎉😊😊❤❤