Electromagnetic Induction | Inductors Connected in Parallel Taking Their Mutual Inductance

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I dont know how i will perform in jee advance 2021 But this channel has geniunely gained me confidence in problem solving Thank U sir I'll try to give my best output in jee advance Fear in mind... Aashirwaad dijiye

siddheshsalfaleservingthen
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Rare concept usually not found in books
Thanks sir the explanation was awesome

adityakishore
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It's one of the best channels for problem solving 🙌 I recommended this channel to my juniors sir and even keep supporting after Oct 3rd 😎

adityamishra
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Rare concept... Enjoyed every bit of it.

sus_tha_coder
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Thank you sir for this awesome channel, you're the best.
I'm subsribed to your channel since 2020 June.
It's been an incredible journey.
I always recommend your channel to my juniors.

UserName-nywd
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Thanks sir yesterday I have learnt about mutual induction in my class
And your explanation is awesome

gouharmaquboolnitp
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Thank you so much sir for all the efforts you have made for us need your blessings for ADVANCED❤❤

schrodingerscat
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nice problem concept similar to jee 2020 q thanks sir

aryansudan
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Sir please take such jee advance level problem sessions 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

funnyshorts
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i did this with loop law too, thanks sir, ok 😄🙏

AdityaGupta-xqud
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Sir can you please upload theory lectures for waves class 11?🙏

unnatagrawal
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Thnks sir, for supporting my jee journey☺️

HOPE-kwej
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sir thank you for all the content! paper ko phod denge

JohnWick-cmoc
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Sir please make one video on pathfinder rotation buyu 40 and 41 🙏🙏

bhaveshkumar
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sir can you please tell why in both the cases(supporting and opposing) if we take perfectly linked coils the L effective is 0 also if L1= L2 and then perfectly linked then would the answer be L+M/2 or 0 (in supporting case)

niharagrawal
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Plz clear one doubt...if the turns are in the same sense in both the coils then mutual and self fluxes will be opposing each other in both coils in parallel connection ...i.e. total flux through first coil would be (L1.I1 - M.I2) and vice versa ...and therefore in the denominator of Leq it should be (L1+L2+2M)....am I correct sir

kakuthism
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Thank you sir 😍
Need your blessings for jee advanced

as.if_
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Thanks sir. for all u have provided.
.Bless me with a good score..

aaryansahu
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Question mein given hota hai mutual inductance leni hai ya nahi?

bleh-zjhy
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Sir how can you tell that the flux due to mutual induction will support the flux. Through inductor(I mean they will be in same direction)

saikhadloya