Tips and Tricks on Modulus Inequality | JEE , NDA & Other Competitive Exams | Ashish Sir

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Tips and Tricks on Modulus Inequality | JEE , NDA & Other Competitive Exams | Ashish Sir
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STEP BY STEP SOLUTION FOR VALUE OF x:
|2x-1|<5
-5<2x-1<5
-5+1<2x-1+1<5+1 (ADDING 1)
-4<2x<6
-4/2<2x/2<6/2 ( DIVIDING BY 2)
-2<x<3

Hope it is correct!!!

anilkumardas
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-5<2x-1<5
-4<2x<6
Div by 2
-2<x<3

rupalithakare
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X belongs ( -2, 3 ) Thanks a lot sir
Sir I need more question Can you please help me

sumanagrawal
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Sir home work question |2x-1|<5 is
-2<X<3 thank you sir for teaching us and gave us knowalage

narmadadas
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Sir, the answer is -
-2<x<3 . Sir, please continue these shorts as they are very much useful for us. Thanks sir 😊😊😊😊😊😊😊😊😊😊😊😊😊.

shubhmishra
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Sir live classes ka schedule kya h bta dena aap pls ☺️☺️

krishgaming
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Thank you Sir
Answer is (-2)<(x)<(3)

MrKaushal
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The answer is:
-2 < x < 3
Thanks sir that trick will help me a lot

avs
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Hello Sir, can we add the LHS and RHS two different inequalities? Eg. 2x-y>3 and 3x+y>7 added to give 5x>10?

anushaaaa