Electrical PE Exam - Per-Unit (PU Conversion)

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An explanation of the per-unit conversion formula for percentage impedance.
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Thanks for the video. It would be really helpful to have another vid where you go through one typical PE problem using the per-unit analysis. I find this to be one of the most simple yet frustrating topics on the PE.

bucknelljay
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You stated that one of the assumptions in 3 phase system analysis is a POWER base. That is not correct - the proper base in such analyses is MVA (Mega-Volt-Amps) which includes the "imaginary" power present, and the reactance part of the impedance. Z =( KV^2)/MVA.

walterbrown
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Thank you. Lucid explanation on per unit conversion.

muhammadtanvir
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The per unit value of Z22kV line = (2 +j 3.5) Ω on a 15 MVA Base is:
How to solve this one?

HamzasaeedKhan
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But how does this work with transformers damnit!

darylreuben
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