Calculus 2, Exam 3 Review, (Series)

Review problems for a calculus 2 exam that covers series. Topics include alternating series test, ratio test, root test, absolute convergence, conditional convergence, Taylor polynomials, and power series.

[standarddirect]

You should know that these are GREAT videos! Please keep making them.

[multicultures]

Didn't study. This helped me review a lot thanks.

[nicolasstencel]

Video helped me tremendously on my test. You should make more

[glorymanheretosleep]

I don't know how it is possible, but all those examples and my professor still managed to ask some really out-of-this world questions that you can't find anywhere on youtube.

[marisagranado]

Thank you so much for this video! I appreciate how you went a little bit more in depth with the limits, which is part of what was giving me trouble

[Fausto_moh]

this helped me recap on so many things that i forgot for my test tomorrow. Thank you.

[seppe]

1:07:37 for x= 6: the n-th term is: (n! * 2^n)^2/(2n!) <=> in the denominator we can distribute the 2's over the n and n-1 and so forth because they both exist out of n terms. We then can cross out equal terms in the denominator and numerator(do this yourself and don't forget the entire denominator is squared). After this simplification we get for our n-th term: (2n)/(2n-1)*(2n-3)/(2n-4)*... and so on. Notice all these fractions are multiplied and greater than one. Thus, if we take the limit of the n-th term, as n goes to infinity, we will get positive infinity. Thus the series diverges.

[evanevan]

You're the best!! Time to not fail my finals

[siphilipe]

Great! Thanks all the way, till 1:21:29.

[mariannakwan]

This is the greatest thing ever, thank you!

[ahmed]

@1:02:50 I guess you forgot to add the -2 to the absolute x, it should be |x-2|

[thy]

for the integral test, why didn't you check 3 conditions if the test will apply?

[briannasingh]

At 19:00, the limit converges to 2, not infinity (still divergent).

[hummakavula]

At 43:27, shouldn't it be infinity * (1/e) instead?

[toddj.]

#8 is infinity/e=infinity; it's not infinity(e)=infinity

[Midchie]

wait, so I thought if there is a limit of the series, it is convergent. I mean if there the sequence approaching to a real number, doesnt that mean that it is convergent? Im confused, please help!

[Jkfgjfgjfkjg]

There is more than one way to skin a cat...