F324 Rings polymers and analysis June 2014 Q2b - 4 from www.ChemistryTuition.Net

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These videos have been extremely helpful.

austinoladoye
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Exam tomorrow!! For question 4 i'm a bit unsure about how you know that the triplet and the quartet means you have a CH2--CH3, I  thought it would be R-CH3 and then either a benzene ring with a CH group or a HC--CO? Thank youuu

SB-brnl
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Thank you for the videos sir
you make nmr question seem really easy
whats the best way to approach an NMR question in the exam?

thank you

zannatul
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I was wondering how you deduced straight away that Ch2COH was attached to the benzene ring? Thanks!

laurachoi
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Great video Thanks, but for 3a why do you have to swap the r groups around and why can't the carbxyl group react with the hydroxyl?

skar
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When you draw amino acids in its 3D form, does it matter which groups go on which bond, i.e. does the COOH always have to go at the top if you get what I mean, or do the groups have to be placed into a specific order to show the reflection (optical isomer) Many thanks for your videos.

margesimpson
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For 2dii, Why can compound G be a 12 long carbon chain with Aldehyde groups at both ends and a double bond in the middle? Wouldn't it split the chain in half and add an aldehyde group to the split ends. Even though it would make 2 of the product, it still only makes hexane- 1, 6 - dial, which is what the question is asking. Thanks

harrywales
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sir a quick question about 3c(iii)
wen u hydrolyse it with acid why is it NH2+ instead of NH3+?
lost a lot of mark on that question
thanks

zannatul
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HC-O at 3.99 ppm, how do you know its C=O i thought it was just for single C-O?

sadaquekhan
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in 3b why is there no HC-N but there is a HC-O? for the peaks

juggi
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