Time and Work - Shortcuts & Tricks for Placement Tests, Job Interviews & Exams

Crack the quantitative aptitude section of Placement Test or Job Interview at any company with shortcuts & tricks on Time and Work. Extremely helpful to crack entrance exams like MBA, Banking – IBPS, SBI, UPSC, SSC, Railways etc.

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0:00 Quantitative Aptitude
0:47 just INVERT
3:30 A can work 5 times faster than B and takes 60 days less than B to complete the work. In how many days does A and B individually can complete the work?
6:42 If 24 men can finish a work in 10 days, then find the number of days required to complete the same work by 30 men?
10:04 A can do a work in 3 days. B can do the same work in 6 days and C can do the same work in 7 days. If they work together, in how many days will they take to complete the work?
13:07 P and Q can do a work in 12 days. Q and R can do the same work in 16 days, and R and P can do it in 24 days. Find the time in which P, Q and R can finish the work together?
16:31 P can do a work in 30 days. Q is 25% more efficient than Pin completing the same work. In how many days will complete the work?
19:29 If 3 men can do a work in 2 days and 4 boys can do the same work in 6 days, then in how many days will the same work be
23:05 Sita and Gita can do a work in 20 days and 25 days, respectively. Both begin together but after a few days, Sita leaves. Then Gita finishes the remaining work in 10 days. After how many
28:04 When Palone does a work, he takes 25 days more than the time taken by P and Q working together to complete the work. But Q alone takes 9 days more than the time taken by P and Q
36:09 Raj can build a house alone in 16 days but Suraj alone can build it in 12 days. Raj and Suraj work on alternate days. If Raj

[akhilesh]

Q9:: A already is working 8 hours/day . Now we can calculate the no. of days for B to finish if he works for 8hours/day.
B's total hours=8*10=80
if B is working 8hours/day=80/8=10
Now calculate simply A and B working together = 1/12 + 1/10
ans =60/11

[borugaddapriyanka]

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[ashtonlobo]

Easy way to solve Question No 6:
3 men do 1/2 amount of work so 1 men does 1/6 amt of work
4 boys do 1/6 amt of work so 1 boy does 1/24 amt of work
Therefore,
8 Men and 8 Boys do the work in,
8x(1/6)+8x(1/24) = 5/3
Inverting would give 3/5


P.S : I Really like these tutorials.. Now I have more confidence in solving Aptitude questions!

[abhaymhatre]

I'll be honest, I tried so many books and videos but no book/video made this topic easy than you guys did. Kudos. Thank you so much!!!!

[TheSolutionMan]

simple and clean way for ques no. 7-
let n be the days they worked together
we know total amount of work done is 1 so,
( 1/20+1/25 )*n + 10*( 1/25 ) = 1
9n/100 + 2/5 = 1
9n + 40 = 100
n = 60/9 = 20/3

[chitturipoojitha]

You are a life saver sir, taught us with brilliant tricks and now I am able to solve similar problems with ease and effortless, Thanks a ton sir

[samyakjain]

Amazing! who else watching during placement?

[xerxius]

An easier method of solving question 10

just use the normal technique that he described earlier and at the end divide by 2 because only one person works on a given day

Raj does 1/16 work in 1 day
Suraj does 1/12 work in 1 day

Raj + Suraj when working alternating,
= 1/12 + 1/16 work in 2 days
= 1/2*( 1/12 + 1/16) work in 1 day
= 7/96 work in 1 day

Raj + Suraj does 7/96 work in 1 day, so, they do the work in 96/7 = 13.75 days

[sravanigoteti]

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[akshaypawar]

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[kewinjoephilip]

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"Extremely easy"
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[stutinayak]

Only this channel is my hope when it comes to quantitative techniques!! Thank you so much, Sir.

[hibajaleel]

For Qn 2
We can use an eqn

M1 ×D1×H1/W1 = M2×D2×H2/W2
Where M1, M2 - no of men
D1, D2 - no of days
H1, H2 - no of hours
W1, W2 - no of work

This eqn can be used in such type of problems. In this question

M1 = 24
M2= 30
D1 = 10
D2 =?

Therefore,
M1×D1 = M2 ×D2
D2 =M1 ×D1/M2
= 24×10/30 = 8 days

😇😇😇😇

[theDRAMA]

Last question - more simple solution
:- total work in 1 day = 7/96.
~ 7/96work*x days =1(total work)
~ x= 13.7 😎😎

[subhradas]

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[byrrajuabhilashraju]

Question 7
Lcm of 20 and 25 is 100.
Efficiency of sita and Gita 5 & 4.
Gita for 10 days= 4*10.
Remaining 60 both has done.
60÷9 = 20/3....
u can do like previous model too.

[amandeepsaluja]

9th question can be done in a simpler way. I got the same ans doing less calculation.
A's one day work = 1/12 [8hrs per day]
B's one day work = 1/8 [10hrs per day]
if 1/8 work is done in 10 hrs, the amount of work done in 8 hours will be 1/10
now we have both A and B 8 hrs work per day

1/12 + 1/10 = 11/60(one day's work together)
total time taken = 60/11 days

[sahilprasantachoudhury]

Self referential note:
Solution of 9Q.
A's 1 hour's work = 1/(12 ×8)
B's 1 hour's work= 1/(8×10)
(A+B)' s 1 hour's work = 1/96 + 1/80
(A+B)'s 8 hour's (or 1 day's)work = (80+96) X 8/(96×80)
Total number of days= 96×80/(80+96)×8 = 60/11 days (Ans)

[shahidaparveen]

For 36:12 Mt thought process is..
Let Raj takes x days and Suraj takes y days while working at alternative days.
X/16 + Y/12 = 1
Simplifying...
3X + 4Y = 48
Now, values of X and y must be the closest..
Half the left most value i.e. 48/2=24 as both are working alternate days...
Values of X may be 6, 7, 8 and corresponding values of y becomes 7.5, 6+3/4, 6. Closest pair is 7 and 6+3/4....
Total days = 13+ 3/4

[justlikethat]

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