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Calculus| If ๐ข= ๐ฅ^3+๐ฆ^3+๐ง^3+3๐ฅ๐ฆ๐ง | show that ๐ฅ ๐๐ข/๐๐ฅ+๐ฆ ๐๐ข/๐๐ฆ+๐ง ๐๐ข/๐๐ง=3๐ข
ะะพะบะฐะทะฐัั ะพะฟะธัะฐะฝะธะต
In this video I describe about the partial derivative with the help of a question.
That is
If ๐ข= ๐ฅ^3+๐ฆ^3+๐ง^3+3๐ฅ๐ฆ๐ง
show that ๐ฅ ๐๐ข/๐๐ฅ+๐ฆ ๐๐ข/๐๐ฆ+๐ง ๐๐ข/๐๐ง=3๐ข
That is
If ๐ข= ๐ฅ^3+๐ฆ^3+๐ง^3+3๐ฅ๐ฆ๐ง
show that ๐ฅ ๐๐ข/๐๐ฅ+๐ฆ ๐๐ข/๐๐ฆ+๐ง ๐๐ข/๐๐ง=3๐ข