Physics - Optics: Diffraction Grating (6 of 7) Resolving Power=? of Diffraction Grating

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In this video I will find the resolving power of the diffraction grating.

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Your videos are the reason that now I m loving physics 🕴️

merisabahar
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This is excellent. Professor, you and your team are the best at figuring out what content students need. I really needed this lecture to help me figure out resolving power of diffraction grating.

valeriereid
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thank you!! saving my life for IB physics

KrisCurrent
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Mr. Michel, why do we multiply the width of the slit with number of lines per centimeter? What does N mean anyways?

andrewjustin
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First time I have come to this channel amazing content with good 👍explanation

AbhishekKumar-jggq
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Love you sir, you method is very great nd easy to understand.

JunaidTariqsatti
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Thank you for your teaching method which is really helpful. I have two questions regarding two equations : 1) Why resolving power should be greater than average lambda over difference lambda ? 2)Is there any proof that resolving power is equal to order multiply number of slits?

MN-mjok
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thanku sooo much sir. helped me so much. wish you were my phys professor.

AdityaNand
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erase the side calcucations lol..those made me panic while seeing at first

SuperShaneHD
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it was really helpfull sir. thnku very much. god bless u.

Ajay-oese
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In ur experimental calculation u written lambda instead of R.?

Physics_in_ಕನ್ನಡ
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Your Derivation is Wrong. N is not the number of lines per cm, it is the number of slits on which the light falls. So, you should not multiply the length of the Grating by the line density to get N. What you need is the width of that tiny area on which the light falls on the grating. Then multiplying by line density of the Grating that quantity gives you the number slits on which the light falls and got diffracted. Kindly got educated and don't fake it.

pullingrabbitsouttaahat
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i love ur videos but there's one thing i dont like, u use a very think marker and its very hard to see on mobile phones

junaidmughal