C Programming Tutorial 50, String Functions pt.1

[YTHandle]

4:03 >When you get a vietnam flashback

[SangoProductions]

50th? hot damn. I'm glad I didn't look linearly through the tutorials for this, or else I would have already been at the end of the semester before I found it.

[jtlpe]

I just wanted to thank you for the tutorials. I am learning a lot from you tutorials, good job!

[HCOSzifon]

"if you print a size_t, make sure to use %u instead of %i" -- *NO! DO NOT do that!* It leads to *undefined behavior.* The *one and only appropriate format specifier* for size_t is "%zu". Nothing else.

[tcbetka]

Because the size of a pointer (char*) is 4 bytes on a 32-bit machine. Your *str variable is a POINTER, not a char or a string. Since all pointers are either 4-bytes on a 32-bit machine, or 8-bytes on a 64-bit machine, then it will return that size with a pointer

[iTzAdamX]

@lludmill I don't think that there is size_type in C, only in C++. From what I've found on the internet, size_t is guaranteed to be able to store the result of the sizeof operator, and the size_type is guaranteed to be able to hold the length of any string.

[iTzAdamX]

I'm not sure if this is what you're asking, but whenever you put some text inside of quotes, the compiler automatically allocates memory for that string and gives you a char* to that memory.

[lludmill]

Thanks for the tutorials, I am a little confused about size_t.Could you explain, what is size_t, and what is the difference between size_t and size_type
Thanks

[iTzAdamX]

@xSpectrumGaming It really depends on what you're trying to do. C++ will run on any OS and it will run faster. However, C# is easier to learn and write. In my opinion though, C++ is better than C#.

[lludmill]

Why not use int instead of size_t, what will be the disadvantage

[thewhisperinyourears]

SO you saying for exaple that we do not have to make an array for the compiler to make a allocatation because the *pointer already does that?

[wowedcanbewowed]

at 7:24 he wants to compare the first 3 letters, What if I want to compare the LAST 3 letters? How can I do that?

ex.
1 *bob*
*bob*
I want to scan the last 3 letters of each word.

[iTzAdamX]

@lludmill If someone had a computer where the size of an int was 2 bytes, then it may not be possible to hold the size of some data structures, like a really big array.

[michaelwangzim]

I am a little confused here... Isn't *name a pointer here? if so, why strlen(name) but not strlen(*name) shouldn't that be the dereference of the pointer? Thanks!

[captainzizo]

there is something wrong when you call the char as a pointer actually you are calling the adress of the string but not the string itself

[m.mohammad]

i still dont understand why you start with char *name