Exercise 2 solution : Python tutorial 78

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This is solution of exercise 2

[CodeClock]

i think this is the best solution
def ispalindrome(a):
if a[0:]==a[-1::-1]:
return print("true")
return print("false")
a=input("enter the string")
ispalindrome(a)

[nehalzaman]

def palindrome(txt):
return txt == txt[-1::-1]
print(palindrome(input("Enter text: ")))

[MrZeekkhan]

SIR HARSHIT OF THANKS ADN RESPECT FROM PAKISTAN

[mubbashar]

Achieved it in a different way: :D In your assignment forgot word[::-1] so create my own logic to reverse
def is_palendrom(word):
length = len(word)
length = length + 1
i = 0
j = 0
inputValue = ""
while i < length:
if i == 0:
j = -1
else:
j = -i
inputValue += word[j]
i = i + 1
print ("inputValue rotated", inputValue)
if word == inputValue:
return True
else:
return False

print ("Is Pelandrom : ", is_palendrom('madam'))


it works :) but your code is simple i think i followed the KISS logic :D

[prem_patel]

i solved like this -

#python 3.7.1

def p(x):
if x[-1].lower()== x[0].lower():
print(" true ")
else:
print(" false ")

y = input("")
print(p(y))

[rawquesh]

name = input("enter your name ")
pname = name[::-1]
if name == pname:
print("True")
else:
print("False")

[GamingwithMooon]

def is_palindrom(a):
if a[::-1] == a:
return "It is a palindrom"
return "Not a palindrom"

word = input("Enter a word to check for palidrome : ")
print(is_palindrom(word))

[MrNile]

name = input('enter a name:')

def palindrome(name):


if name == name[::-1]:
return True
else:
return False

print(palindrome(name))

[junaidjaved]

cant thank you enough for this amazing code

[shivam_shahi]

def is_palindrome(a):
if a == a[::-1]:
return True
else:
return False

[bhushanghate]

def palindrome (name):
If name[-1]==name[0]:
return True
return False
Name=Input("enter your name")
Print(palindrome (name))

[SohailMughal]

name = input('Enter a name : ')
name = name.lower()
def is_palindrome(a):
if a == a[::-1]:
return True
else:
return False
print(is_palindrome(name))

[shashankkumar]

def palin(a):
b=len(a)
if a==a[::-1]:
return True
return False


a=input("enter string:")
print(palin(a))

[dr.immpetus]

def Pali(name):
if name[::-1]==name:
return "Palindrome"
return "Not Palindrome"

name=input("Enter name : ")
print(Pali(name))

[shishirkatiyar]

My solution -
def is_palindrome(string):
string1=string.lower()
length=len(string1)
string_rev=string1[::-1]
for i in range(length):
if string1[i]==string_rev[i]:
return True
else:
return False
string=input("Enter any string: ")
print(f"The input string is palindrome : {is_palindrome(string)}")

[dheeraj]

I implemented it using a different logic. Compared the extremities of the given word to check if the are the same alphabet using for loop and stored the results, which I later checked if any of the result was not palindrome.


def palindrome_check(word):
heap = ""
for i in range(0, len(word)):
if word[i] == word[(len(word)-1-i)]:
heap += "palindome"
else:
heap += "NotPalindrome"
if 'NotPalindrome' in heap:
print("The given word is not palindome")
else:
print("The given word is palindrome")

palindrome_check("abcba")

[prateikjindal]

string = input("Enter any word: ")
a =string[::-1]
if a == string:
print("same")
print("not")
#maine aisa banaya tha...

[RashidAli-covt]

def palindrom (words):
if words == words[::-1]:
return True
words =input("enter words : ")
print(palindrom(words))

[xNnja]

def is_palindrome(a):
if a[0] and a[-1] ==a[0] and a[-1]:
return True
else:
return False

a=input("Enter Your Name : ")
print(is_palindrome(a))

[RajGupta-pgcx]

Sir,
Maine aapne se different string bnai h.. But usme
User se input lekar output me show ho jayega ki wo palindrome word h ya nhi.. Jo mene method use kiya h kya wo shi h..