Harvard MIT Challenge You To Solve This!

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Havard MIT Challenge You To Solve This 2018 HMMT Algebra Problem! #maths #mathematics #hmmt #algebra

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I solved it in 1 minute. Here is my approach:
Let x = 3^n
By substituting x in given equation
And equating the powers of 3 we get
2n[3^(6n)] = 1
3^(6n) = 1/(2n)
Then I tried by taking 6n = -1, not possible.
I took 6n = 1, n = 1/6 the equation is valid.
So the answer is x = 3^(1/6)

ankithsai