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Vector: Figure shows ABCDEF as a regular hexagon. What is the value of AB + AC + AD + AE + AF
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here we find the resultant of vectors in regular hexagon by using parallelogram principle
Vector: Figure shows ABCDEF as a regular hexagon. What is the value of AB + AC + AD + AE + AF
Figure shows ABCDEF as a regular hexagon. What is the value of AB + AC + AD + AE + AF
Figure shows A B C D E F as a regular hexagon. What is the value of A B+A C+A D+A E+A F (a) A O (...
Figure shows ABCDEF as a regular hexagon. What is the value of ....
Figure shows ABCDEF as a regular hexagon. What is the value of (𝐴𝐵)+ (𝐴𝐶)+(𝐴𝐷)+(𝐴𝐸) +(𝐴𝐹)...
Figure shows ABCDEF as a regular hexagon. What is the value ofAB AC AD AE AF(a) AO(b) 2AO(c)...
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0580/22/F/M/18 (IGCSE) Paper 22, Q7 Vectors, Regular Hexagon
ABCDEF is a regular hexagon. Show that : AB+AC+AD+AE+AF=6 AO where O is the centre of the h...
`ABCD` is a parallelogram Fig. 2 (c ) .64. AC` and (BD) are its diagonals. Show that `
PFP-2 motion in a plane/ parallelogram law/Triangle law/polygon law/numericals adda #11thphysicsadda
In the given figure, ABCDEF is a regular hexagon, which vectors are:
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The diagram shows a regular hexagon. Prove AB-BC+CD-DE+EF-FA=0.
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`AB` is a side of a regular hexagon `ABCDEF ` and is of length `a` with `A` as the origin and
Let ABCD is a parallelogram and `vecAC, vecBD` be its diagonal, then `vecAC +vec BD` is
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13) Let ABCDEF be a regular hexagon with centre 'O'. Show that AB+AC+AD+AE+AF =3AD =6AO
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