Two identical capacitors 1 and 2 are connected in series. The capacitor 2 contains a dielectric ...

Two identical capacitors 1 and 2 are connected in series. The capacitor 2 contains a dielectric slab of constant \( k \) as shown. They are connected to a battery of emf \( v_{0} \) volt. The dielectric slab is then removed. Let \( Q_{1} \) and \( Q_{2} \) be the charge stored in capacitor before removing the slab and \( Q_{1}{ }^{\prime} \) and \( Q_{2}{ }^{\prime} \) be the values after removing the slab. Then
(1) \( \frac{\mathrm{Q}_{1}}{\mathrm{Q}_{1}}=\frac{\mathrm{k}+1}{\mathrm{k}} \)
(2) \( \frac{\mathrm{Q}_{2}}{\mathrm{Q}_{2}}=\frac{\mathrm{k}+1}{2} \)
(3) \( \frac{\mathrm{Q}_{2}}{\mathrm{Q}_{2}}=\frac{\mathrm{k}+1}{2 \mathrm{k}} \)
(4) \( \frac{Q_{1}}{Q_{1}}=\frac{k}{2} \)